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2 years ago

Someone I need help this is my last time on this app I need help (correct answers only )

Mathematics

2 answers:

Airida [17]2 years ago

8 0

Answer:

FDDU

Step-by-step explanation:

RUR

Harrizon [31]2 years ago

3 0

Answer:

ok options?

Step-by-step explanation:

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I = prt Time = 3 years Interest Rate = 5% Principal = $7,430 Use the information to answer the question. How much interest is pa

bearhunter [10]

I = prt

p = 7430
r = 5%....turn to decimal = 0.05
t = 3

I = (7430)(0.05)(3)
I = 1114.50 <===

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3 years ago

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What is the unit price for one cd if 3 cds cost 29.85?

zavuch27 [327]

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3 years ago

Multiplying fractions

mixas84 [53]

2/9 x -1/4

2x1=2 9x4=36

2/36

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1/18

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3 years ago

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Can someone plz help me with this :)

Yanka [14]

It is c because I just know what I’m doing

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3 years ago

Crash testing evaluates the ability of an automobile to withstand a serious accident. A simple random sample of 12 small cars we

morpeh [17]

Answer:

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (small cars), of size n1=12 has a proportion of p1=0.6667.

$p_1=X_1/n_1=8/12=0.6667$

The sample 2, of size n2=15 has a proportion of p2=0.3333.

$p_2=X_2/n_2=5/15=0.3333$

The difference between proportions is (p1-p2)=0.3333.

$p_d=p_1-p_2=0.6667-0.3333=0.3333$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{8+5}{12+15}=\dfrac{13}{27}=0.4815$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.4815*0.5185}{12}+\dfrac{0.4815*0.5185}{15}}\\\\\\s_{p1-p2}=\sqrt{0.0208+0.0166}=\sqrt{0.0374}=0.1935$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.1935=0.3793$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.3333-0.3793=-0.046\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.3333+0.3793=0.713$

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

8 0

3 years ago