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3 years ago

9

The diagram shows 2 identical charged particles. How does the potential energy and the force of repulsion changes as the charges

are bought closer together?

1 answer:

maw [93]3 years ago

5 0

Answer:

did you get an answer?????

Explanation:

I'm in usatestprep and I really need an answer

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The voltage or potential difference provides the ____ required for electrons to travel through a circuit

galben [10]

Answer:

a. push

Explanation:

Voltage is the force or pressure that is responsible for pushing the charge or electrons to flow in a closed-looped electrical circuit. This flow of electrons (charge) is called the electric current. It is also defined as the difference in electric potential per unit charge between two points in an electric field.

5 0

3 years ago

Two very large parallel sheets a distance d apart have their centers directly opposite each other. The sheets carry equal but op

andrew-mc [135]

Answer:

(A) F

Explanation:

See it in the pic.

8 0

4 years ago

Read 2 more answers

How much work must be done in the car to slow it from 100km/h to 50km/h

Brilliant_brown [7]

Answer:

$-96.465m$ joule

Explanation:

Let m = mass of the car and v1 = initial velocity and v2 = final velocity

Given.

Initial velocity = 100 km/h

final velocity = 50 km/h

What is work done in the car to slow it from 100km/h to 50km/h?

$v1=100km/h=27.78m/s$

$v2=50km/h=13.89m/s$

The work done in the car to slow it from v1 to v2.

w=Δk

$w=k2-k1$

$w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}$

$w=\frac{1}{2} m(v2-v1)^{2}$

$w=\frac{1}{2}\times m(13.89 -27.78)^{2}$

$w=\frac{1}{2}\times m(-13.89)^{2}$

$w=\frac{1}{2}\times m\times (-192.93)$

$w=-96.465m$ joule.

Therefore, the work done is $-96.465m$ joule

7 0

3 years ago

Which statements describe how a machine can help make work easier? Select two options.

ad-work [718]

Answer:

It can put out more force than the input force by decreasing the distance through which force is applied.
It can apply a force to an object in a different direction than the force applied to the machine.

Explanation:

Assuming the machine is a simple machine, such as a lever or pulley, the machine will not do any more work than is put into it. However, it can change the magnitude or direction (or both) of the input force required to achieve a particular output force.

Because the machine does not increase the work done, if the output force is greater, the output distance must be less.

The applicable observations are ...

It can put out more force than the input force by decreasing the distance through which force is applied.
It can apply a force to an object in a different direction than the force applied to the machine.

6 0

3 years ago

The polar coordinates of the collar A are given as functions of time in seconds by r = 2+ 0.7 t2 ft and ????= 3.5t rad. What are

r-ruslan [8.4K]

Answer with explanation:

Part a)

$v_{radial}=\frac{dr}{dt}=\frac{d(2+0.7t^{2})}{dt}\\\\v_{radial}=1.4t\\\\\therefore v_{radial}|_{t=4}=1.4\times 4=5.6ft/s\\\\v_{angular}=r|_{t=4}\times \frac{d\theta }{dt}=13.2\frac{3.5t}{dt}=46.2fts^{-1}\\\\\therefore v=\sqrt{v_{radial}^{2}+v_{angular}^{2}}\\\\v=46.53ft/s$

Part b)

$a_{radial}=\frac{d^{2}r}{dt^{2}}=\frac{d^{2}(2+0.7t^{2})}{dt^{2}}\\\\a_{radial}=1.4ft/s^{2}\\\\a_{angular}=r\times \frac{d^{2}\theta }{dt^{2}}\\\\a_{angular}=r\times \frac{d^{2}(3.5t) }{dt^{2}}\\\\\therefore a_{angular}=0\\\\\therefore Accleration=1.4ft/s^{2}$

8 0

3 years ago