Im thinking D. It is 100 times larger
C. Forces are always in pairs
It is considered parts of the Hydrosphere because water condenses in clouds and falls as precipitation so it is a vital part of the hydrosphere.
Answer:
a)0.674 kg b) 2.2 s c) 0.9 m/s²
Explanation:
The amplitude of the ball (xo) = 11.0cm, half way between its equilibrium point its maximum displacement x = 11 cm / 2 = 5.5 cm = 5.5 / 100 in meters = 0.055 meters, speed at this point = 27.2 cm /s = (27.2 / 100) in m/s = 0.272 m/s,
spring constant K = 5.5 N/m
a) The mass of the ball (m) can be calculated using the formula below
v =√ (x²o - x²)K/m
make m subject of the formula
v² = (xo² - x²) K/m
m = K ( xo² - x²) / v²
m = 0.674kg
b) The period of the oscillation can be calculated by the following formula
T = 2π√ (m /K)
substitute the values into the formula
T = 2 × 3.142 × √ (0.674/ 5.5) = 2.2s
c) The maximum acceleration of the ball which occurs at the maximum displacement of the ball can be calculated by the following formula
a = K / m × x ( maximum displacement of the body) = 5.5 / 0.674 × 0.11 = 0.9 m/s²
Answer: A.) v = 2πr/T
Explanation:
The tangential speed of an orbiting object can be obtained by the product of the radius of the orbit and the angular speed of the object in a circular motion.
This the tangential seed can be represented mathematically as :
Tangential speed (v) = angular speed(ω) × radius(r)
v = r × ω --------(1)
Recall:
ω = 2π/T
Substituting ω = 2π/T in equation (1)
v = r × 2π/T
v = 2πr/T
