Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
D. He forgot to subtract the area of the base from the total surface area of the cube.
Step-by-step explanation:
He is only spray washing the *exterior* of the building; the base is not exposed so it will not be spray washed, which means Richard can use less water.
Hope this helps. :)
A and C are complementary
B is supplementary
Answer:
2x2+9x−1=x
Step 1: Subtract x from both sides.
2x2+9x−1−x=x−x
2x2+8x−1=0
Step 2: Use quadratic formula with a=2, b=8, c=-1.
x=
−b±√b2−4ac
2a
x=
−(8)±√(8)2−4(2)(−1)
2(2)
x=
−8±√72
4
x=−2+
3
2
√2 or x=−2+
−3
2
√2
Step-by-step explanation:
This is what I got but I'm not 100% positive. I checked it on a calculator and it seemed to check out.
Answer:
21
Step-by-step explanation:
5×3=15
7×3=21
