Answer:
C. to explore the composition of Mars
Explanation:
Initially, in 2019, an unmanned mission is planned to orbit the moon. The spacecraft would flyby the moon. In 2020's, the Exploration Mission 2 would be a manned mission on the same path around the moon. This would be the base for future goal of collecting samples from mars. In later of 2020's unmanned spacecraft would be sent to mars and a robot would collect the samples from the Martian surface. In 2030's, a crew would be sent to Mars.
The half-life equation is written as:
An = Aoe^-kt
We use this equation for the solution. We do as follows:
5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes?
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE
Find a formula for G(t) , the amount of goo remaining at time t.G(t)=?
G(t) = 176e^-0.02t
How many grams of goo will remain after 50 minutes?
G(t) = 176e^-0.02(50) = 64.75 g
Remember that a cation will be smaller than its neutral atom, and an anion will be larger than its neutral atom. This would automatically eliminate answer choices A and D.
Also keep in mind that atomic radii decreases from left to right as you move along a periodic table. It also decreases from bottom up.
Atomic radii increases as you move from right to left and as you go from up to down.
As bromine is higher up in the periodic table than Iodine, it would have a smaller radius. Iodine would have a larger radius.
The correct answer is B. Br
Answer:
Succinic acid
Explanation:
The most common possibility is succinic acid
As it has decimals after whole no till hundredth it contains OH and C in most of the cases .
Let's check for succinic acid
- C4H_6O_6
- 4(12)+4(16)+6
- 64+48+6
- 118u
Yes approximately equal
Molecular formula is.
(CH_2)_2(CO_2H)_2
