The answer for this question is c.
Answer:
28 different ways
Step-by-step explanation:
This is a combination question. Combination has to do with selection.
Total number of element in the set = 8
Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}
Total number divisible by 6 or 8 is 6
The number of ways we can choose 6 items from 8 is expressed as;
8C6 = 8!/(8-6)!6!
8C6 = 8!/(2)!6!
8C6 = 8*7*6!/2!6!
8C6 = 8*7/2
8C6 = 56/2
8C6 = 28 ways
Hence there are 28 different ways
Answer: 7
Step-by-step explanation:
7
Answer:
See below
Step-by-step explanation:
When we talk about the function 
, the domain and codomain are generally defaulted to be subsets of the Real set. Once 
and 
such that 
for 
. Therefore,
![\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%5Ccdot%7D%3A%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5Cto%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5C%5D)
![\[x \mapsto \sqrt{x}\]](https://tex.z-dn.net/?f=%5C%5Bx%20%5Cmapsto%20%5Csqrt%7Bx%7D%5C%5D)
But this table just shows the perfect square solutions.
You can either write 2.4 as 12/5 ( an improper fraction) or as 2(2/5) (a mixed number).
