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nataly862011 [7]

3 years ago

7

PLZ HELP WILL PICK BRAINIEST

1 answer:

fenix001 [56]3 years ago

3 0

Answer:

i dont know for shore but i think it is part 2

Step-by-step explanation:

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .

$\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2$ .

$\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2$ .

Solve this equation for $u$ :

$\displaystyle \frac{u^{2} + 1}{u^{2}} = 2$ .

$u^{2} + 1 = 2 u^{2}$ .

$u^{2} = 1$ .

Given that $0 \le u \le 1$ , $u = 1$ is the only possible solution.

$\cos^{2}{x} = 1$ ,

$x = k \pi$ , where $k\in \mathbb{Z}$ (i.e., $k$ is an integer.)

Given that $0 \le x < 2\pi$ ,

$0 \le k$ .

$k = 0$ or $k = 1$ . Accordingly,

$x = 0$ or $x = \pi$ .

8 0

2 years ago

Read 2 more answers

All most done thanks for hanging in there

Ber [7]

Answer:

Angle CBE

Step-by-step explanation:

They share the same degree. Or are the same angle in a different place with a different name.

7 0

2 years ago

Read 2 more answers

Can someone help and explain and do the solution pls :(

brilliants [131]

Consider ∆JWZ and ∆JKZ

WZ~KJ (given)

<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)

JZ~JZ (common)

Therefore,

∆JWZ~∆JKZ by SAS congruence rule.

JW~ZK by CPCT.

6 0

2 years ago

What is the least common multiple of 9, 17, and 51? A. 51 B. 102 C. 153 D. 867

Luden [163]

Answer:

<h2>C. 153</h2>

<em>Hope</em><em> this</em><em> helps</em>

<em>shshsgshsh</em>

3 0

3 years ago

Graph the linear equation y=-2/5x+2

Anvisha [2.4K]

Start at (0,2) and draw a dot. Then, go up 2 units, and right 5 times. Draw a dot. Now connect the 2 dots and extend the line.

Now, it's graphed! :)

4 0

2 years ago