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3 years ago

Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year)

2 answers:

8 0

So.. .hmm let us see there are well.. in a MYR a million years, you said it :)
so 1,000,000y/myr or you can flip it around as myr/1,000,000y

for the sake of ratio, either one is valid
you can say, 1,000,000 years to a MYR or
one MYR to 1,000,000 years
same thing

now... let's see km... well, there are 1,000meters to 1km
and there are 100cm to 1meter
so.. let us use those ratios, flipped around as needed

$\cfrac{110\cancel{km}}{1\cancel{myr}}\cdot \cfrac{1000\cancel{m}}{1\cancel{km}}\cdot \cfrac{100cm}{1\cancel{m}}\cdot \cfrac{1\cancel{myr}}{1,000,000y}\implies \cfrac{\square ?}{\square ?}
$

cancel the units below and above as needed m/m cancels out, km/km cancels out, and so on

jenyasd209 [6]3 years ago

6 0

Answer:

$110\ \text{km/myr} =11\ \text{cm/yr}$

Step-by-step explanation:

To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?

Solution :

Using metric conversions,

1 kilometer = 1000 meter

1 meter = 100 centimeter

So, 1 kilometer = 100,000 centimeter

and 1 million year = 1,000,000 year

$1\ \text{km/myr} =\frac{100000}{1000000}\ \text{cm/yr}$

$1\ \text{km/myr} =0.1\ \text{cm/yr}$

So, $110\ \text{km/myr} =110\times 0.1\ \text{cm/yr}$

$110\ \text{km/myr} =11\ \text{cm/yr}$

Therefore, $110\ \text{km/myr} =11\ \text{cm/yr}$

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How many 1/3 inch are in 3/4 inch?

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Answer:

2, 1/3 inches in 3/4

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so there are 2 1/3 inches in 3/4, this is a sort of rough explanation I reccomend going on Khan Academy and looking for something to help you there

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3 years ago

A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A

Readme [11.4K]

Answer:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=6.5$ represent the sample mean for Atlanta

$\bar X_{2}=6.7$ represent the sample mean for Chicago

$s_{1}=0.5$ represent the sample deviation for Atlanta

$s_{2}=0.7$ represent the sample standard deviation for Chicago

$n_{1}=100$ sample size for the group Atlanta

$n_{2}=110$ sample size for the group Chicago

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Based on the p-value, what is your conclusion?

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3 years ago

Read 2 more answers