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olga2289 [7]
3 years ago
12

Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year)

Mathematics
2 answers:
Blizzard [7]3 years ago
8 0
So.. .hmm let us see there are well.. in a MYR a million years, you said it :)
so 1,000,000y/myr  or you can flip it around as myr/1,000,000y

for the sake of ratio, either one is valid
you can say, 1,000,000 years to a MYR or
one MYR to 1,000,000 years
same thing

now... let's see  km... well, there are 1,000meters to 1km
and there are 100cm to 1meter
so.. let us use those ratios, flipped around as needed

\cfrac{110\cancel{km}}{1\cancel{myr}}\cdot \cfrac{1000\cancel{m}}{1\cancel{km}}\cdot \cfrac{100cm}{1\cancel{m}}\cdot \cfrac{1\cancel{myr}}{1,000,000y}\implies \cfrac{\square ?}{\square ?}


cancel the units below and above as needed m/m cancels out, km/km cancels out, and so on

jenyasd209 [6]3 years ago
6 0

Answer:

110\ \text{km/myr} =11\ \text{cm/yr}

Step-by-step explanation:

To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?

Solution :

Using metric conversions,

1 kilometer = 1000 meter

1 meter = 100 centimeter

So, 1 kilometer = 100,000 centimeter

and 1 million year = 1,000,000 year

1\ \text{km/myr} =\frac{100000}{1000000}\ \text{cm/yr}

1\ \text{km/myr} =0.1\ \text{cm/yr}

So, 110\ \text{km/myr} =110\times 0.1\ \text{cm/yr}

110\ \text{km/myr} =11\ \text{cm/yr}

Therefore, 110\ \text{km/myr} =11\ \text{cm/yr}

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True or False: The slope of the line that passes through (9, 9) and (6, 4) is 3/5.
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point (9, 9)

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Solve the system by elimination.(show your work)
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Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

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Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

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2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

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Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

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0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

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0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

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0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

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0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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