Answer:
A.
Step-by-step explanation:
Answer:
Hello!
Step-by-step explanation:
a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have
Evaluate the integral to solve for y :
Use the other known value, f(2) = 18, to solve for k :
Then the curve C has equation
b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:
The slope of the given tangent line is 1. Solve for a :
so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).
Decide which of these points is correct:
So, the point of contact between the tangent line and C is (-1, -3).
Question:
Consider the expression
When using the inspection method the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is?
Answer:
The constant to add is 4
Step-by-step explanation:
Given
First, we need to get an expression that has x + 3 has its factor.
Represent this expression with:
Expand
Group like terms
Compare the above expression to:
However, we only consider solving for k
Subtract 3 from both sides
Substitute -2 for k in
So, the expression that has a factor of x + 3 is
To get the constant term to add/subtract, we have:
Open brackets
Collect Like Terms
Answer:
no
Step-by-step explanation: