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yan [13]
3 years ago
8

Which three lengths CANNOT be the lengths of the sides of a triangle

Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

I believe 21 cm

Step-by-step explanation:

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Kaitlyn solved the equation for x using the following calculations. Negative 5.4 + x = 12.2. Minus 5.4. x = 6.8. What error, if
omeli [17]

Step-by-step explanation:

The equation that Kaitlyn solved is as follows :

-5.4+x=12.2

The steps to solve it as follows :

Step 1. Add 5.4 to both sides,

-5.4+x+5.4=12.2+5.4

Step 2. 5.4 will cancel out as both have opposite signs

x=17.6

But Kaitlyn solved it as :

5.4.x=6.8

She has multiplied -5.4 and x which is wrong. The correct answer is 17.6.

3 0
3 years ago
A. (4,0)<br> b. (3,2)<br> c. (6,4) <br> d. (0,0)
belka [17]
(3,2) because it is in the direct center
6 0
3 years ago
Can someone help me
KatRina [158]

Let's recall that in a parallelogram:

1. The opposite sides are paralell

In our exercise. sides CZ and KG are paralell. And so do sides KC and GZ.

2. Those opposite sides are equal in length.

3. The opposites angles are equal. In our exercise, angle C and G are equal and so do angles K and Z.

4. That also mean that the angles at the top of the figure are supplementary. It means they add up to 180 degrees. We have the same situation with the two angles at the bottom of the parallelogram.

In our case then:

\angle\text{ C = }\angle\text{ G }\Rightarrow\text{ C = 50}\circ\text{ , G = 50}\circ

Now, we can find the measure of angles K and Z, as follows:

\angle C\text{ + }\angle Z\text{ = 180}\Rightarrow\text{ 50 + }\angle Z\text{ = 180 }\Rightarrow\text{ }\angle Z\text{ = 180 - 50}\angle Z\text{ = 130}\circ\text{ }\Rightarrow\angle K\text{ = 130}\circ

3 0
1 year ago
ronaldo delivers the papers at the rate of 6 papers in 24 minutes. how much longer would it take him to deliver 56 papers than 4
UkoKoshka [18]

We are given

Ronaldo delivers the papers at the rate of 6 papers in 24 minutes

so, number of papers =6 in time =24 minutes

so, firstly we can find rate

rate = ( number of papers)/( time taken)

r=\frac{6}{24} =\frac{1}{4}

now, we can find times

Time for 56 papers:

we are given

number of papers =56

rate is

r=\frac{1}{4}

now, we can find time

t_1=\frac{56}{r}

t_1=\frac{56}{\frac{1}{4}}

t_1=224min

Time for 41 papers:

we are given

number of papers =41

rate is

r=\frac{1}{4}

now, we can find time

t_2=\frac{41}{r}

t_2=\frac{41}{\frac{1}{4}}

t_2=164min

now, we can find time difference

t=t_1-t_2

so, we can plug values

t=224-164

t=60 min..............Answer


8 0
3 years ago
Read 2 more answers
Find the product of <br> (−9−11i) and its conjugate.
grin007 [14]

Answer:

202

Step-by-step explanation:

First, we can find the conjugate of (-9 -11i)

Given a complex number a + bi, the conjugate would be a - bi.

So, the conjugate of -9 -11i is -9 + 11i.

Now, we multiply!

(-9-11i)(-9+11i)

This resembles the special product (a+b)(a-b) which multiplies out to a^2 - b^2

To apply this we subtract the square of the second number from the first.

(-9)^2 - (11i)^2

81 - 121i^2

i^2 is -1, so we can substitute it in:

81 + 121 = 202

7 0
3 years ago
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