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3 years ago

8

Which three lengths CANNOT be the lengths of the sides of a triangle

1 answer:

kogti [31]3 years ago

4 0

Answer:

I believe 21 cm

Step-by-step explanation:

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The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original

evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

${:\implies \quad \sf 5(s+8)=65}$

${:\implies \quad \sf 5s+5\times 8=65}$

${:\implies \quad \sf 5s+40=65}$

${:\implies \quad \sf 5s=65-40}$

${:\implies \quad \sf 5s=25}$

${:\implies \quad \sf s=\dfrac{25}{5}=5}$

${:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}$

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

8 0

2 years ago

The area of the trapezoid

ELEN [110]

Answer:

<h2>A = 82.5 in²</h2>

Step-by-step explanation:

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

$A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2$

7 0

3 years ago

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The work shows how to use long division to find (x2 + 3x –9) ÷ (x – 2).

Maksim231197 [3]

2x+3x -9. You can simplify this to 5x-9.

8 0

3 years ago

Which could be the measure of <br> A.) 38<br> B.) 42<br> C.) 44<br> D.) 52

vichka [17]

Well you can check what type of angle it is! like depending on how it is slouched like a right angle is 90° for example.

3 0

3 years ago

Need help with math question

mote1985 [20]

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12 Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16 (now write the left hand side as a square)

(y-4)^2=4x+28

(y-4)^2=4(x+7) factored...

vertex is (-7,4)

4 0

3 years ago

Read 2 more answers