Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
Answer:
B--StartFraction pi Over 2 EndFraction radians
Step-by-step explanation:
Answer:
46
Step-by-step explanation:
There is an open + in the middle. It does not have any brackets around it. Therefore you do it at the very last.
Left side of the plus sign.
[16 ÷ (2 + 3*2)] Do the multiplication inside the parenthesis ( 2*3) first.
= [16 ÷ (2 + 6)] Add inside the parenthesis.
= [16 ÷ 8 ] Do the division
= 2
Right side of the open plus sign
[4 * (36 - 25)] Do the subtraction first.
[4 * 11 ] Do the multiplication
44
Now combine both right and left side.
2 + 44
46
The answer is 46.
Answer:desired
Step-by-step explanation: i think it's like 4/8 then the theoretical property
Is 1/8
Answer:
line B I hope this help!! good luckkk
