A homeowner is planting a vegetable garden. The location

Sandy had 10 dollars in her collection. she gave 3 to her younger sister. her parents were so impressed that they quadrupled (le

Natali5045456 [20]

She had $100 and she gave $3 to her sister so $10-$3=$7 and her parent quadrupled her remaining dollars which was $7 so $7x4=$28 the answer is $28

3 0

3 years ago

Read 2 more answers

The number of cartons of apples sold at a store each day for eight days is shown. 30 , 40 , 51 , 30 , 34 , 20, 30, 45 Determine

nikitadnepr [17]

Answer:

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

Step-by-step explanation:

Given :

1.)

Data: 30 , 40 , 51 , 30 , 34 , 20, 30, 45

Rearranged data : 20, 30, 30, 30, 34, 40, 45, 51

Mean = ΣX / n = 280 / 8

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

2.)

90 , 72 , 48 , 84 , 77 , 72, 50, 83

Rearranged data : 48, 50, 72, 72, 77, 83, 84, 90

Mean (m) = ΣX / n = 576 / 8

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

6 0

2 years ago

Pre-Calc: Find all the zeros of the function.

uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)