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tatiyna
3 years ago
12

A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue

chips, and 6 yellow chips. The player wins $5 if a red chip is
selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W
represent the total amount won, where W= X - 15. What is the mean of W?
$10.50
B
$4.50
-$4.50
D
- $6.50
E
-$10.50
Mathematics
2 answers:
adelina 88 [10]3 years ago
4 0

Answer:b. 4.50

Step-by-step explanation:

muminat3 years ago
4 0

Answer:

C. -$4.50

Step-by-step explanation:

To find the mean of W we must first find the mean of X. So, 10/20*5+4/20*10+6/20*20=10.5

Then because mean is impacted by transformations, the mean of W=the mean of X-15=10.5-15=-$4.50

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Last week, the price of cherries at the corner deli was $4.99 per pound. This week, cherries at the same deli are on sale at a 1
ANEK [815]

Answer:

Your answer should be 15.905625, if it's not 15 percent off per pound.

Step-by-step explanation:

Multiply 4.99 x 3.75 then multiply that answer (18.7125) by .15

That will leave you with 2.806875, which then you subtract that from 18.7125

That will give you your answer, 15.90...

4 0
3 years ago
write a simplified polynomial expression in the standard form to represent the area of the rectangle below x-4 5x+2
Ann [662]

The area of the rectangle is 5x^{2} -18x-8

Explanation:

One side of the rectangle is x-4

The another side of the rectangle is 5x+2

The formula to find the area of the rectangle is length × width

Area = length × width

Substituting the values, we have,

\begin{aligned}\text { Area } &=(x-4)(5 x+2) \\&=5 x^{2}+2 x-20 x-8 \\&=5 x^{2}-18 x-8\end{aligned}

Thus, the area of the rectangle is 5x^{2} -18x-8

3 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

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KatRina [158]

Answer:

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Step-by-step explanation:

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Decide if this statement is true or false.
AVprozaik [17]

Answer:

Step-by-step explanation:

I believe it’s false

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