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IrinaK [193]
2 years ago
9

1/6 of a birthday cake is left over from a party. The next day, it is shared among 7 people. How big A piece of the original cak

e did each person get?
Mathematics
2 answers:
N76 [4]2 years ago
4 0

Answer:

j

Step-by-step explanation:

mr Goodwill [35]2 years ago
4 0
<h3>Answer:    1/42</h3>

Explanation:

Draw 6 identical rectangles side by side as shown in figure 1 in the diagram below. Shade one of the rectangles to represent 1/6 of the cake left over.

Now draw in horizontal lines (see figure 2) to split the leftover amount into 7 equal portions. Notice that we have a 7 by 6 grid of tiny rectangles. There are 7*6 = 42 tiny rectangles in total.

Each person will therefore get 1/42 of the original cake when splitting up this last leftover slice.

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nika2105 [10]

Answer: the fourth one

Step-by-step explanation:

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3 years ago
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A. pat x-10 is a negative
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stiks02 [169]

Answer:

(4,1)

Step-by-step explanation:

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6 0
3 years ago
1. The sum of the three consecutive members of the geometric sequence is 13. The proportion of the third and the first member is
aev [14]
If a = first term and r = common ratio we have

a + ar + ar^2 = 13   and ar^2 / a = r^2 = 9

so r = 3

and a + 3a + 9a = 13 
so a = 1

so they are  1,3 and 9 

2.
in geometric series we have

4 , 4r ,4r^2 , 60

Arithmetic;
 4,  4r , 4r + d ,  4r + 2d

so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30 
so d = 30 - 2r 
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0

2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r  = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24

and the numbers are 4*3 =  12 , 4*3^2 = 36

first 3  are  4 , 12 and 36  ( in geometric)
and last 3 are 12, 36 and 60  ( in arithmetic)

The 2 numbers we ause are 12 and 36.





7 0
3 years ago
H&gt;
arsen [322]

Answer:

C

Step-by-step explanation:

3*-4

3 0
3 years ago
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