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masha68 [24]
3 years ago
6

What is the value of the product of -20/48 times 6 in simplified form

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
8 0
-20/48 x 6 =   \frac{-20}{48}    x  \frac{6}{1}

I would cancel out the 6 in the numerator and the 48 in the denominator 
Now I have <u />\frac{-20}{8}  or <u />\frac{-5}{2} reduced.

-5 ÷ 2  = -2 1/2 and that is the answer in simplest form
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What are the next three terms in the pattern 2, 6, 18, 54, ...?
castortr0y [4]

Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

It is a geometric sequence and the common difference is 3.

The general form of a geometric sequence is: a, ar, ar², ar³, . . .

Here a = 2 and r = 3.

$ n^{th} $ term of a Geometric progression is $ ar^{n - 1} $.

Note that the fourth term is 54.

i.e., $ ar^3 = 54 $

$ \implies ar^4 = ar^3 . r = 54 . 3 = 162 $.

Similarly, $ ar^6 = 162 \times 3 = 486 $.

Also, $ ar^7 = ar^6 . r = 486 \times 3 = 1458 $.

Hence, OPTION B is the answer.

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3 years ago
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3 years ago
X^2+x-12=0 solve ASAP
zzz [600]
X^2+x-12=0 factors out into (x+4)(x-3) so the answer is: x=-4, x=3
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HELP ME RN PLEASEEEE<br> [WILL GIVE BRAINLY TO CORRECT AND BEST EXPLAINED ANSWER]
VMariaS [17]

Answer:

\boxed {\boxed {\sf d= \sqrt{34}}}

Step-by-step explanation:

We want to find the distance between two points, so the following formula is used.

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.

We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:

  • x₁= -2
  • y₁= -1
  • x₂= 3
  • y₂= 2

Substitute the values into the formula.

d= \sqrt {(-2-3)^2+(2--1)^2

Solve the parentheses.

  • -2 -3 = -5
  • 2--1 = 2+ 1 = 3

d= \sqrt{(-5)^2+(3)^2

Solve the exponents.

  • (-5)²= -5*-5= 25
  • (3)²= 3*3=9

d= \sqrt{25+9}

Add.

d= \sqrt{34}

This radical cannot be simplified, so the distance between the two points is <u>√34</u> and <u>choice 3 </u> is correct.

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3 years ago
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