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9966 [12]
3 years ago
5

What number should be placed in the box to help complete the division calculation?

Mathematics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

this goes there 850

Step-by-step explanation:

plus th anwser is 155 R0

myrzilka [38]3 years ago
4 0

Answer:

The number that goes in the box is 850. If I am wrong, please correct me.

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The total mass of Sandeep and his sister, Leela, is 54.75 kg. The total
krok68 [10]
He is 38 kg.


I'll use only the first letters of their names, to make it simpler:

S+L=54.75
S+M=105
M=4L

S+4L=105
105-54.75=4L-L=3L
L=50.25/3=16.75
S=54.75-16.75=38
6 0
3 years ago
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A park ranger observed the number and ages of children who visited the park on a Friday morning. The results of his observations
aleksandr82 [10.1K]
ANSWER

The number of children between the ages of 9 and 15 who visited the park is
20


EXPLANATION


The number of children between the ages of 9 and 15 who visited the park are those within the age group 9 to 12 and 12 to 15.


We can from the graph that, the height of the bar that corresponds to the age group 9 to 12

= 14
and the height of the bar that corresponds to the age group 12 to 15

= 6


The sum of the two frequencies

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8 0
3 years ago
Y = |x| translated one unit to the left
Assoli18 [71]

Answer:

It is moved one unit to the right.

Step-by-step explanation:

8 0
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The boxed definition of absolute value states that |a|=-a if a is a negative number. Explain why |a| is always nonnegative, even
Temka [501]

Final answer:

Since absolute values determine the distance between the number and the value whether the value is positive or negative. As distance is always positive.

Thus, |a| is always nonnegative, even though |a|=-a for negative values of a.

Step-by-step explanation:

Step 1

It is said that |a| is always nonnegative even though even though |a|=-a for negative values of a.

Step 2

This is because by the definition of an absolute value, any real number inside an absolute value symbol || will always be positive.

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2 2/4 devided by 1/6
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(15 is your answer)

Divide numerator by denominator, cancel out any common factors
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