Answer:
Top right.
Step-by-step explanation:
So we want a line with a slope of 3 and passes through (2,5).
To do so, we can use the point-slope form.
The point-slope form is:

m is the slope and x₁ and y₁ is an ordered pair.
Thus, let m be 3, y₁ be 5, and x₁ be 2. Thus:

Our answer is the top right :)
Answer:
A). Surface area = 222 cm²
Volume = 180 cm³
B). Surface area = 375 cm²
Volume = 360 cm³
C). % increase in surface area = 67.57%
% increase in volume = 100%
Step-by-step explanation:
In the figure attached base of a prism has been given.
A). Surface area of the prism = (Perimeter of the base of the prism) × height + 2(area of the base)
Perimeter of the base = 5 + 3 + 2 + 2 + 2 + 3 + 5 + 8
= 30
Area of the base = 8×5 - 2×2 = 36 cm²
Surface area of the prism = 30×5 + 2×(36)= 222 cm²
Volume of the prism = volume of the bigger prism - volume of the smaller prism cut off
= 8×5×5 - 2×2×5
= 200 - 20
= 180 cm³
B). Surface area of the prism if it's height is 10 cm,
Surface area = 30×10 + 2×(36) = 372 cm²
Volume of the prism = 8×5×10 - 2×2×10
= 400 - 40
= 360 cm³
C). Increase in surface area = 372 - 222 = 150 cm²
% increase in the surface area =
= 67.57%
Increase in volume = 360 - 180 = 180 cm³
% increase in volume =
= 100%
Answer:
2
Step-by-step explanation:
20/10=2
Sq root (54) =
sq root (9*5) =
3 * sq root (5)
Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.