Answer:
The mass of the steel bar is 26.833 grams
Explanation:
<u>Step 1: </u>data given
ΣQ gained = ΣQ lost
Q=m*C*ΔT
with m = mass in grams
with C= specific heat capacity ( in J/(g°C))
with ΔT = change in temperature = T2-T1
Qsteel = Qwater
msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)
Mass of steel = TO BE DETERMINED
mass of water =⇒ since 1mL = 1g : 80 mL = 80g
Csteel =0.452 J/(g °C
Cwater = 4.18 J/(g °C
initial temperature steel T1 : 2 °C
final temperature steel T2 = 21.3 °C
initial temperature water T1 =22 °C
final temperature water T2 = 21.3 °C
<u>Step 2:</u> Calculate mass of steel
msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)
msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)
msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)
msteel = -234.08 / 8.7236
msteel = -26.833 g
Since mass can't be negative we should take the absolute value of it = 26.833g
The mass of the steel bar is 26.833 grams
