Answer:
See explanation below
Explanation:
To solve this problem, we need to use the expression of half life decay of concentration (or mass) which is the following:
m = m₀e^-kt (1)
In this case, k will be the constant rate of this element. This is calculated using the following expression:
k = ln2/t₁/₂ (2)
Let's calculate the value of k first:
k = ln2/2.7 = 0.2567 d⁻¹
Now, we can use the expression (1) to calculate the remaining mass:
m = 8.1 * e^(-0.2567 * 2.6)
m = 8.1 * e^(-0.6674)
m = 8.1 * 0.51303
m = 4.16 mg remaining
Two electrons in it's first energy level; eight electrons in it's second energy level; and six valence electrons in it's outermost energy level
Answer:
In the presence of salt water and oxygen the coating will not corrode. As long as zinc coating is present and remains intact corrosion is not possible.
Explanation:
Here it is given that a tin is present so firstly tin is made of a chemical element
which belongs to carbon family in periodic table of group 14.
It is a silvery,soft, white metal with a bluish tinge.
Now the covering which is been done on the tin is Zinc.
so, zinc is known to be served as a sacrificial coater.
Their is an amazing reason behind zinc coating being so effective and intact i.e. Its own corrosive properties are such that it stops corrosion.
Their is a process which is known as a galvanic corrosion which refers to that "ZINC" defers to the metal to which it is protecting.
It is even more electrochemically active than iron itself.
Here, it is mentioned that zinc coating gets chipped but the coating remains intact. So, if the zinc is not removed from the tin's surface it will not get corroded when it is exposed to salt water and oxygen.
Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
