The third substance or agent which produce the film between the interface of two immiscible liquids and thus stabilize the system are known as an emulsifying agent.
Since the solubility of the liquids depends on the polarity of the mixing liquids the thumb rule of solubility is like dissolves like that means polar liquid dissolves in polar liquid only and vice versa. For two immiscible liquids, the emulsifying agent is used which does not chemically change the polarity of liquids but acts as bridge between immiscible liquids, the polar end of the emulsifier attach to the polar liquid and the non-polar end of the emulsifier attach to the non-polar end and thus help in dissolving.
Therefore, the one end of the emulsifier is polar and the other end is non-polar
Explanation:
A and D
A. A pressure equal to that of the osmotic pressure will result in reverse osmosis.
D. The movement of the solvent particles from the concentrated solution to the dilute solution is known as reverse osmosis.
During osmosis, water molecules from the less concentrated right side, will flow into the left side til they equilibrate- at equilibrium both sides will have the same concentration of solute.
Thus, the water passes through the membrane due to the difference in osmotic pressure/ solute concentration on either side of the membrane, this means that the water moves from regions of high osmotic pressure/concentration to regions of low osmotic pressure /concentration.
Water potential equal to the pressure potential shifts the equilibrium, resulting in the movement of solute.
<h3> φ= φs+φp</h3>
However, in reverse osmosis, solute molecules move from regions of high solute concentration, to regions of low solute concentration across the membrane.
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Answer:
A)A compound that donates protons
Explanation:
for B it is the defination of bases
The mass in grams 550 mL of salt water with a density of 1.50 g/cm³ is 825grams.
<h3>DENSITY:</h3>
- The mass of a substance can be calculated by multiplying the density of the substance by its volume. That is;
Mass = density × volume
- According to this question, the volume of the salt is 550mL while its density is given as 1.50g/mL. The mass is calculated as follows:
Mass = 1.50g/mL × 550mL
Mass = 825grams.
Therefore, the mass in grams 550 mL of salt water with a density of 1.50 g/cm³ is 825grams.
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There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
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Avogadro's number
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