Because sodium only has 1 electron in its outer shell so it wants to give away the 1 electron to have a full outer shell. When it gives away 1 electron is has 1 more protons than it does electron and since protons have a positive charge it has a charge of +1
Le us discuss how we should approach this problem. We know that there are two states. The first state is when P₁ = 1 bar and V₁ = 1.59 L. The second state is when P₂ = 80 bar. We are asked to find V₂. At constant temperature, we use Boyle's Law.
P₁V₁ = P₂V₂
V₂ = P₁V₁/P₂ = (1 bar)(1.59 L)/(80 bar)
<em>V₂ = 0.02 L</em>
The particles in a solid are tightly packed and locked in place. ... The particles in a liquid are close together (touching) but they are able to move/slide/flow past each other. The particles in a gas are fast moving and are able to spread apart from each other.
Answer:
Compound 1 is a molecular compound
Compound 2 is an ionic compound
Compound 3 is a molecular compound
Explanation:
Let us review the properties of ionic and molecular compounds.
A molecular compound has a low melting and boiling point. This is as a result of weak intermolecular forces. Also, molecular compounds do not conduct electricity both in solid and liquid state because they are composed of molecules and not ions.
On the other hand, ionic substances have very high melting and boiling points. They are very strong solids that often have a dull appearance and do not conduct electricity in the solid state.
Compounds 1 and 3 have the properties of molecular substances hence they are classified as such. Compound 2 displayed the properties of an ionic substance hence it is classified as such.
