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Gala2k [10]
3 years ago
7

What is the median value of the data set shown on the line plot?

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer: 30

Step-by-step explanation:

You put the numbers from least to greatest. 27,28,28,29,29,29,30,30,30,31,31,31,33,34. Then the median would be 30 and 30. So then you would add the two numbers 30 + 30 then divide by 2. 60/2 and the answer would be 30. Hopefully that was helpful.

You might be interested in
I need the answer for this
Svetach [21]

Answer:

535.9 ft²

Step-by-step explanation:

Since there are 360° in a circle, and 240° is 2/3 of 360°, we can say that the area of the bolded sector is <em>2/3 the area of the whole circle</em>. The area of a circle with a radius of r is πr², or approximately 3.14r², so the area of the whole circle is ≈ 3.14(16)² = 3.14(256) = 803.84 ft². Taking 2/3 of this gets us 803.84 * (2/3) ≈ 535.9 ft²

6 0
3 years ago
Jose Canseco hit three fifth-deck home runs at SkyDome/Rogers Centre during his career, including the first ever at the stadium
Mademuasel [1]

Answer:

187 ft/s

Step-by-step explanation:

Given in the y direction:

v₀ = 0 ft/s

Δy = 75 ft

a = 32 ft/s²

Find: t

Δy = v₀ t + ½ at²

(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²

t = 2.165 s

Given in the x direction:

Δx = 480 ft

a = 0 ft/s²

t = 2.165 s

Find: v₀

Δx = v₀ t + ½ at²

(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²

v₀ = 187 ft/s

4 0
3 years ago
What is 48901x120412/12321 with a fraction of 6/9 + 29181041/21841x2912311203? It was one of my math questions couldn't find it
zimovet [89]

4468886443222234578889953

7 0
3 years ago
If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
How much do 10 pieces of candy cost if 1000 pieces cost ​$90<br> ​?<br> 10 pieces of candy cost
Masteriza [31]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the cost per candy:

90/1000 = 0.09

Multiply this by the number of candy pieces you need:

0.09 x 10 = 0.9

They would cost $0.90

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
4 years ago
Read 2 more answers
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