PT=y,TR=x+3,QT=2y,TS=3x-1 I'm confused and u really need help. My teacher isn't the greatest and wasn't much help.

Mathematics

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer:

y=10, x=7

Step-by-step explanation:

Since the diagonals of a parallelogram bisect each other, PT should be equal to TR and QT should be equal to TS. So, y=x+3 and 2y=3x-1. Multiplying the first equation by 3 gives you 3y=3x+9. Using elimination to subtract these two equations gives you y=10. And since y=x+3, substitute y=10 there. 10=x+3, x=7.

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Fofino [41]

Answer:

$\frac{6}{k-6}$

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ ÷ $\frac{(k-6)^2}{k(k-6)}$ × $\frac{6(k-10)}{k(k + 6)}$ . We know that division is simply multiplication by the reciprocal, so that whole equation will turn into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ × $\frac{k(k-6)}{(k-6)^2}$ × $\frac{6(k-10)}{k(k+6)}$ . Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into $\frac{6}{k-6}$ which is our final answer, as it cannot be simplified further.