I count five 'k's there, so that part of the expression is
k⁵ .
Two 'n's form the rest of it, so that part is n² .
The parts are multiplied, so the simplest form of the expression is
k⁵ n² .
Complete question:
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?
A) segment a double prime b double prime = segment ab over 2
B) segment ab = segment a double prime b double prime over 2
C) segment ab over segment a double prime b double prime = one half
D) segment a double prime b double prime over segment ab = 2
Answer:
A) segment a double prime b double prime = segment ab over 2.
It can be rewritten as:
Step-by-step explanation:
Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.
We know segment A"B" equals segment AB multiplied by the scale factor.
A"B" = AB * s.f.
Since we are given a scale factor of ½
Therefore,
The equation that explains the relationship between segment AB and segment A"B" is
Option A is correct
Answer:
tq eddy porada for eddy ame
Answer:The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.
Step-by-step explanation:
Answer:
y=3/2x+11/2
Step-by-step explanation:
Hello! Sorry I just saw this
Anyways, let's continue
first, we need to find the equation of the line with the one that is (-2,-4) and (2,2)
first, we need to find the slope
the equation for slope is y2-y1/x2-x1
so let's label the points
x1=-2
y1=-4
x2=2
y2=2
now plug it in
2-(-4)/2-(-2)=6/4=3/2
now, let's turn it into a line
the point-slope form is y-y1=m(x-x1) (m=slope)
now, plug it in
y-(-4)=3/2(x-(-2))
simplify to
y+4=3/2(x+2)
turn into y=mx+b format
y+4=3/2x+3
subtract 4 on both sides
y=3/2x-1
Now for the line that is parallel.
Parallel lines have the same slopes, so you automatically know that the new line will be y=3/2x+b
To make sure (-3,1) is a solution to the point, put 1 as y and -3 as x
1=3/2(-3)+b
1=-9/2+b
add 9/2 on both sides
b=11/2 or 5.5
now, put it into the equation
y=3/2x+11/2
Hope this helps!