Step-by-step explanation:
(a-b)^2=(a^2-2*a*b+b^2)
4*(x^2-2x+1)-9=4x^2-8x+4-9=4x^2-8x-5
if you have to calculate the Δ
there is it: 4x^2-8x-5=0
Δ=b^2-4*a*c=64-4*4*(-5)=64+80=144
-b±Δ/2*a=8±12/8=
=8+12/8=20/8|:4=5/2
=8-12/8=-4/8|:4=-1/2
It doesnt matter anymore, im gonna fail and nobody has been answering my question honestly, or not even reading it at all..
2 answers:
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Answer:
Final answer is .
Step-by-step explanation:
Given that P(A)= .50, P(B)=.80 , and P(A and B)=.20.
Now we need to find about what is the value of P(B/A).
So apply the formula of compound probability :
P(A and B) = P(A)*P(B/A)
Plug the given values into above formula
0.20 = 0.50*P(B/A)
0.50*P(B/A) = 0.20
Hence final answer is .
Answer:
Yes, the sum of any two sides is greater than the third.
Step-by-step explanation:
To determine whether the provided sides are the sides of a triangle check if the sum of two sides is more than the third side.
The length provided are: 8.5, 13 and 19.1.
- Consider the sides 8.5 and 13:
The sum is:
This sum is greater than the third side 19.1
- Consider the sides 8.5 and 19.1:
The sum is:
This sum is greater than the third side 13
- Consider the sides 13 and 19.1:
The sum is:
This sum is greater than the third side 8.5
Thus, the sides 8.5, 13 and 19.1 are sides of a triangle.