Answer: he invested $46062.5 at 6% and $23031.25 at 10%
Step-by-step explanation:
Let x represent the amount which he invested in the account paying 6% interest.
Let y represent the amount which he invested in the account paying 10% interest.
He puts twice as much in the lower-yielding account because it is less risky.. This means that
x = 2y
The formula for determining simple interest is expressed as
I = PRT/100
Considering the account paying 6% interest,
P = $x
T = 1 year
R = 6℅
I = (x × 6 × 1)/100 = 0.06x
Considering the account paying 10% interest,
P = $y
T = 1 year
R = 10℅
I = (y × 10 × 1)/100 = 0.1y
His annual interest is $7370dollars. it means that
0.06x + 0.2y = 7370 - - - - - - - - - -1
Substituting x = 2y into equation 1, it becomes
0.06 × 2y + 0.2y = 7370
0.12y + 0.2y = 7370
0.32y = 7370
y = 7370/0.32
y = $23031.25
x = 2 × 23031.25
x = 46062.5
Answer: $76,244.51
Step-by-step explanation:
You need to use the compound interest formula here.
First of all however, you need to convert the terms to monthly figures because the interest is compounded monthly.
4% in months = 4 / 12 = 4/12%
6 years = 6 * 12 = 72 months
Now use the compound interest formula:
= Amount * (1 + rate) ^ number of years
= 60,000 * ( 1 + 4/12%) ⁷²
= $76,244.51
-1,1,3,5,and 7 in that order
The answer is 8 and yea it’s 2 steps first u have to remove the constant so u subtract 74-2=72 and 2-2=0. After u get rid of the constant u divide both sides by 9 basically 72/9 and 9/9 which is 8. So n is equal to 8 I hope this helped. I know it can be confusing