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3 years ago

A square park has an area of 1⁄16 square miles and a length of 1⁄4 mile. What is the width of the park?

1 answer:

4 0

Width: 1/4 Explanation: First you set up the problem as 1/16 divided by 1/4, then you change the division sign to multiplication and then you flip the second fraction which is 1/4, you should have 4/1, next you have a problem like 1/16 x 4/1 1x4= 4 and 16x1=16, did you get 1/4 as your product? If you didn’t, repeat the steps and try as many times until you get it, it is the only way to learn. Thank you for asking this question and have a great Evening! :)

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Answer this correct and you are a true legend 9 + 10 = ? ...

S_A_V [24]

Answer:

AcORdinG To MY CaLCulAtIoNS ItS 21

Step-by-step explanation:

Logic :)

5 0

3 years ago

Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x

AfilCa [17]

Answer:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0

2 years ago

Matt plans to put concrete on a rectangle portion of his driveway. The portion is 8 feet long and 4 inches high. The price of co

Snowcat [4.5K]

The answer is d. 6 feet

3 0

3 years ago

If y varies inversely as x and y=16 when x=4, find y when x=3

iren [92.7K]

Answer:

21.33 to nearest hundredth

Step-by-step explanation:

Inverse Variation is y = k / x where k is a constant.

Plug in the given values to find k:-

16 = k/4

k = 4*16 = 64 so the equation of variation is y = 64/x.

So when x = 3, y = 64/3 = = 21.33 to nearest hundredth.

6 0

3 years ago

Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1

Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

$x' =x (12 -x - \dfrac{1}{2})$

$y' = y( 20 -y - x)$

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

$x' =x (12 -x - \dfrac{y}{2}) = 0$

$\dfrac{x}{2} (24 -2x - y) = 0$

x = 0 or 24 - 2x - y = 0 ----- (1)

Also

$y' = y( 20-y-x) = 0$

y( 20 -y - x) = 0

y = 0 or 20 - y - x = 0 ----- (2)

By solving (1) and (2);

we get x = 4 and y = 16

Suppose x = 0 from (2)

y = 20

Also;

if y = 0 from (1)

x = 12

Thus, the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

6 0

2 years ago