Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
9. 10x + 5y is the equation for larger watermelons + smaller watermelons (you did not provide information about the medium watermelons, so we must assume given the options you miswrote one of them). We can hold NO MORE than 500 pounds, so 10x + 5y must be smaller than 500. The best answer is C assuming that "5y" represents your "Medium Watermelons"- because smaller watermelons are stated to be 5 and medium ones should therefore be between 5 and 10, the option provided by A wouldn't make since because 3 pounded watermelons are not "medium" in comparison to the "small ones" that are heavier/bigger. Your best option is C, 10x + 5y < 500, the exact answer technically would be 10x + 5y <= 500.
Answer:
DC = 10.93 cm , AC = 9.8 cm
Step-by-step explanation:
From trigonometry;
⇒ Tan 60 = AB/BD
⇒AB = BD Tan 60 ( where BD = 4 cm )
⇒ AB = 6.93 cm
Also, AB=BC , therefore;
⇒ BC = 6.93 cm
⇒ Cos 60 = BD/AD
⇒ AD = BD/ Cos 60 = 4/Cos 60
⇒ AD = 8 cm
From Pythagoras theorem;
⇒
=
+
=
+ 
⇒ AC =
= 9.80 cm
⇒ DC = BD + BC = 4 + 6.93
⇒ DC = 10.93 cm
Answer:
17
Step-by-step explanation:
2y+2=36
Let's solve this equation for 2y first. This means get 2y by itself.
So to get 2y by itself I need to undo that addition of 2 next to it.
The inverse operation of addition is subtraction.
I'm going to subtract 2 on both sides:
2y =36-2
2y =34
Now we want to get y by itself so we divide both sides by 2 since division and multiplication are inverse operations:
y= 34/2
y= 17
Answer:
P = 2(n - 6) + 2(n^2 - 8)
Step-by-step explanation:
Remembering that Area = Length times Width, we factor the given function
A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:
A = n^3 - 6n^2 - 8n + 48 factors as follows:
A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)
We can label '(n - 6)' "width" and '(n^2 - 8'
length.
Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:
P = 2(n - 6) + 2(n^2 - 8)