The slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
<h3>How to find the slope of a line?</h3>
given that the equation is 5x - 3y = 2.
now write the equation in standard form y = mx + b
then -3y = 2 - 5x
y = -2/3 + 5x/3
y = 5/3x - 2/3
m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.
Here m1 = 5/3 and m2 = -3/5.
Hence,the slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
Learn more about slope of the line from here:
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Firstly, you have to isolate the X on one side if the equation by doing that you have to divide the numbers that are on the same side of the equation as part of the X.
You’re correct. That’s is the right answer.
The question is missing the figure which is attached below.
Answer:
1620 cm³
Step-by-step explanation:
Given:
The two prisms are similar.
Volume of the smaller prism (V₁) = 60 cm³
Length of the smaller prism (l₁) = 5 cm
Length of the larger prism (l₂) = 15 cm
Now, we know that, for similar figures, the dimensions of the figure are in proportion to each other. Therefore,


This means that, the smaller figure is dilated by a scale factor of 3.
Hence, 
Volume of smaller prism is given as:

Volume of larger prism is given as;
![V_2=l_2b_2h_2\\\\V_2=3l_1\times 3b_1\times 3h_1\\\\V_2=27(l_1 b_1h_1)\\\\V_2=27\times 60=1620\ cm^3\ \ \ \ [\because\ l_1b_1h_1=60\ cm^3]](https://tex.z-dn.net/?f=V_2%3Dl_2b_2h_2%5C%5C%5C%5CV_2%3D3l_1%5Ctimes%203b_1%5Ctimes%203h_1%5C%5C%5C%5CV_2%3D27%28l_1%20b_1h_1%29%5C%5C%5C%5CV_2%3D27%5Ctimes%2060%3D1620%5C%20cm%5E3%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20l_1b_1h_1%3D60%5C%20cm%5E3%5D)
Therefore, the volume of the larger rectangular prism is 1620 cm³.