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3 years ago

What is one half ( 1/2 ) squared?

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer:

$(\frac{1}{2} )^{2} =\frac{1^2}{2^2} = \frac{1} {4}}$

When squaring a fraction, square both numerator AND denominator

Musya8 [376]3 years ago

3 0

The answer is 1/4
1/2x1/2=1/4

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If a = 5, b = 5 and c = 10, what is the value of ac / 2b ?

Sophie [7]

Answer:

The answer is 5 .

Step-by-step explanation:

You have to substitute the values of a, b and c into the expression :

$\frac{ac}{2b}$

Let a = 5,

Let b = 5,

Let c = 10,

$\frac{5 \times 10}{2 \times 5}$

$= \frac{50}{10}$

$= 5$

3 0

3 years ago

A {1,2,3,4}<br> B {2,4,9,16}<br> C {1,2}<br> D {1,2,3,4,9,16}

MaRussiya [10]

Answer:

Step-by-step explanation:

The range of the function consists of the set of output values ( on the right).

So its {2 4 9 16}

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3 years ago

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F(x)=-8x+4 then f^-1(x)= PLEASE HELP!!!

lakkis [162]

F^-1(x)= (x-4)/-8 because it's just finding the inverse function

6 0

3 years ago

Graph this compound inequality 2.5 is equal to or less than x is equal to or less than 4.5

Oxana [17]

Graph this compound inequality 2.5 is equal to or less than x is equal to or less than 4.5

2.5 <= x < = 4.5

We graph this inequality using number line.

Here x lies between 2.5 and 4.5

While graphing, we start with closed circle at 2.5 because we have equal symbol .

Then shade till 4.5. Use closed circle at 4.5.

The graph is attached below.

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3 years ago

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Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0

2 years ago