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marissa [1.9K]
3 years ago
5

What is one half ( 1/2 ) squared?

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

(\frac{1}{2} )^{2} =\frac{1^2}{2^2} = \frac{1} {4}}

When squaring a fraction, square both numerator AND denominator

Musya8 [376]3 years ago
3 0
The answer is 1/4
1/2x1/2=1/4
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If a = 5, b = 5 and c = 10, what is the value of ac / 2b ?
Sophie [7]

Answer:

The answer is 5 .

Step-by-step explanation:

You have to substitute the values of a, b and c into the expression :

\frac{ac}{2b}

Let a = 5,

Let b = 5,

Let c = 10,

\frac{5 \times 10}{2 \times 5}

=  \frac{50}{10}

= 5

3 0
3 years ago
A {1,2,3,4}<br> B {2,4,9,16}<br> C {1,2}<br> D {1,2,3,4,9,16}
MaRussiya [10]

Answer:

B

Step-by-step explanation:

The range of the function consists of the set of output values ( on the right).

So its {2 4 9 16}

7 0
3 years ago
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F(x)=-8x+4 then f^-1(x)= PLEASE HELP!!!
lakkis [162]
F^-1(x)= (x-4)/-8 because it's just finding the inverse function
6 0
3 years ago
Graph this compound inequality 2.5 is equal to or less than x is equal to or less than 4.5
Oxana [17]

Graph this compound inequality 2.5 is equal to or less than x is equal to or less than 4.5

2.5 <= x < = 4.5

We graph this inequality using number line.

Here x lies between 2.5  and 4.5

While graphing, we start with closed circle at 2.5 because we have equal symbol .

Then shade till 4.5. Use closed circle at 4.5.

The graph is attached below.


5 0
3 years ago
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Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
Yanka [14]

Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

\sigma^2 =\frac{1}{5}*[162]

\sigma^2 =32.4

Solving (c): The standard deviation

This is calculated as:

\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0
2 years ago
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