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alexandr402 [8]
3 years ago
8

Jimmy determines that he needs to sell more than $250 worth of fruit at his produce stand in order to make a profit. Which inequ

ality represents the fruit sales, s, in dollars, for which Jimmy will make a profit?
Mathematics
1 answer:
katrin [286]3 years ago
4 0

Answer:

The inequality that represents the fruit sales is s > 250.

Step-by-step explanation:

Let s the fruits sales of Jimmy, measured in dollars. Given that he needs to selle more than $ 250 of fruit at his produce stands in order to make the profit, he needs to satisfy the following inequation or inequality:

s > 250

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Please help me :)))))
svetoff [14.1K]
Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
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Sergio039 [100]

Given:

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The image of the given point after 90 degrees counter clockwise rotation.

Solution:

If a point rotated 90 degrees counter clockwise, then

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Let the given point is P(-5,7). Using the above rule, we get

P(-5,7)\to P'(-7,-5)

Therefore, the image of the given point after 90 degrees counter clockwise rotation is (-7,-5).

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0 is the answer identity

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