All categories

3 years ago

What is the gcd of 1664 4554 1683 4050

Mathematics

1 answer:

storchak [24]3 years ago

4 0

Greatest Common Divisor (GCD) for 1664 4554 1683 4050 is 1.

Explanation

The Greatest Common Divisor (GCD), also known as the Greatest Common Factor (GCF), or Highest Common Factor (HCF), of two or more non-zero integers, is the largest positive integer that divides the numbers without a remainder.

In this example:

Factors of 1664 are: 1 , 2 , 4 , 8 , 13 , 16 , 26 , 32 , 52 , 64 , 104 , 128 , 208 , 416 , 832 , 1664.

Factors of 4554 are: 1 , 2 , 3 , 6 , 9 , 11 , 18 , 22 , 23 , 33 , 46 , 66 , 69 , 99 , 138 , 198 , 207 , 253 , 414 , 506 , 759 , 1518 , 2277 , 4554.

Factors of 1683 are: 1 , 3 , 9 , 11 , 17 , 33 , 51 , 99 , 153 , 187 , 561 , 1683.

Factors of 4050 are: 1 , 2 , 3 , 5 , 6 , 9 , 10 , 15 , 18 , 25 , 27 , 30 , 45 , 50 , 54 , 75 , 81 , 90 , 135 , 150 , 162 , 225 , 270 , 405 , 450 , 675 , 810 , 1350 , 2025 , 4050.

We see that the Greatest Common Factor (Divisor) is 1.

You might be interested in

Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of

GenaCL600 [577]

Close off the hemisphere $S$ by attaching to it the disk $D$ of radius 3 centered at the origin in the plane $z=0$ . By the divergence theorem, we have

$\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV$

where $R$ is the interior of the joined surfaces $S\cup D$ .

Compute the divergence of $\vec F$ :

$\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2$

Compute the integral of the divergence over $R$ . Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

$\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}$

So the volume integral is

$\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5$

From this we need to subtract the contribution of

$\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S$

that is, the integral of $\vec F$ over the disk, oriented downward. Since $z=0$ in $D$ , we have

$\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k$

Parameterize $D$ by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

where $0\le u\le 3$ and $0\le v\le2\pi$ . Take the normal vector to be

$\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k$

Then taking the dot product of $\vec F$ with the normal vector gives

$\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v$

So the contribution of integrating $\vec F$ over $D$ is

$\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4$

and the value of the integral we want is

(integral of divergence of F) - (integral over D) = integral over S

==> 486π/5 - (-81π/4) = 2349π/20

5 0

4 years ago

Bill and Mary Ann went to the Viola bakery. Bill bought 5 pies and 7 donuts for $12.65. Mary Ann bought 6 of each for $12.30.

sweet [91]

Answer:

Pies=$0.85

Donuts= $1.20

Step-by-step explanation:

In the equation let p stand for the number of pies and d stand for the number of donuts.

To solve this set up 2 equations, one representing bill and the other representing Mary Ann.

Bill's equation is 5p+7d=$12.65.
Mary Ann's equation is 6p+6d=$12.30

Then solve using a system of equations. Systems of equations can be solved using elimination or substitution. I will use substitution. Solve bill's equation for p. This gives you $p=\frac{12.65-7d}{5}$ . Then, you can substitute that into Mary Ann's equation. This looks like $6\cdot \frac{12.65-7d}{5}+6d=12.3$ . Solve for d. Once you solve d=1.20. Finally, substitute 1.20 back into either Bill's or Mary Ann's for d and solve for p. No matter which equation you use p=0.85.

3 0

3 years ago

A meatball recipe calls for 2 cups of breadcrumbs for every 5 cups of ground meat. How many cups of breadcrumbs are required for

Ghella [55]

Answer:

1/4 cup for every cup

Step-by-step explanation:

If you divide 2 by 5, you would get this answer. Sorry if it's wrong!

6 0

3 years ago

Suppose you budgeted $2800 for fuel expenses for the year. How many miles could you drive if gas were $2.70 per gallon and your

Julli [10]

Answer:

29037.036 miles

Step-by-step explanation

There are two possible ways to solve this problem.

The first option starts with the $2800 dollars for the years. You first want to divide this by $2.70, because it will give you the amount of gallons of gas you can buy with that money.

2800/2.70 = 1037.037

This means you can buy 1037.037 gallons of gas in the year. Now you need to convert this to miles by multiplying by the amount of miles per gallon.

1037.037 x 28 = 29037.036 gallons

The second way to look at this is dimensional analysis. If you have learned this, then continue on reading this, but if you haven't I might only confuse you. I only suggest this because it can make it a little easier.

For the dimensional analysis, you need to start with what you are given and move to what you need to know, so you will start with the $2800 dollars and move to gallons. $2.70 per gallon and 28 miles per gallon are your conversion factors.

Set it up like this:

$2800 dollars * \frac{1 gallon}{2.70 dollars} * \frac{28 miles}{1 gallon} = 29037.036 miles$

This allows the equation to be more organized, and you can check your work by canceling the units.

Hope this helps.

3 0

3 years ago

What is the answer to <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bz-5%7D%7Bz%2B1%7D%3D%5Cfrac%7B3%7D%7B2%7D" id="TexFormula1" ti

rusak2 [61]

The correct answer is Z=-13

7 0

3 years ago

Read 2 more answers