Including all real and imaginary zeros and taking multiplicities into account, every equation of degree n has exactly n roots
Answer:
<u>The correct answer is Hypotenuse = 3.61 units (Rounding to two decimal places)</u>
Step-by-step explanation:
We can use the Pythagoras theorem formula for solving this questions. It can be expressed symbolically as follows:
Hypotenuse² = First leg² + Second leg²
"The amount of units comprising the hypotenuse squared is equal to the addition of the measure of both legs squared."
Hypotenuse² = First leg² + Second leg²
Hypotenuse = √(First leg² + Second leg²
)
Replacing with the real values:
Hypotenuse = √(3² + 2²
)
Hypotenuse = √(9 + 4
)
Hypotenuse = √13
Hypotenuse = 3.60555
<u>Hypotenuse = 3.61 units (Rounding to two decimal places)</u>
Um, what operations? You didn't list any...
Answer:
32
Step-by-step explanation:
If she started with 28, ad had 50 after she picked, you wold subtract 28 from 50 to find your answer.
