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3 years ago

PERGUNTA 1

Mathematics

1 answer:

Reptile [31]3 years ago

5 0

C I guess

I don’t understand

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The variables x and y are directly proportional, and y = 2

ololo11 [35]

3/2 = 9/x,

so 9 times 2 divided by 3 = 6

A: 6

5 0

3 years ago

which shows one way to determine the factors of 12x^3 - 2x^2 + 18x - 3 by grouping? A) 2x^2(6x - 1) + 3(6x - 1) B) 2x^2(6x - 1)

Eva8 [605]

Answer:

$2x^2(6x - 1) + 3(6x - 1)$

Step-by-step explanation:

Given

$12x^3 - 2x^2 + 18x - 3$

Required

Factorize

To start with; we need to group the expression into two

$(12x^3 - 2x^2) + (18x - 3)$

Factorize each grouped expression, using their common factor

$2x^2(6x - 1) + 3(6x - 1)$

From the list of given options;

Option A is correct

4 0

3 years ago

Determine the factors of the expression x^2 - 9

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

The answer is B.

Use the sum-product pattern

2+3−3−9

Common factor from the two pairs

2+3−3−9x2+3x−3x−9

(+3)−3(+3)

Rewrite in factored form

(+3)−3(+3)

Solution:

(−3)(+3)

‘Hope it Helps!

5 0

2 years ago

If the price of a business math text rose to $120 and this was 10% more than the original price what was the original selling pr

kolezko [41]

Step-by-step explanation:

120*10% =12

10% percent *120

= (10/100)*120

= (10*120)/100

= 1200/100 = 12

120 - 12 = 108.00 is original price of math text

5 0

2 years ago

Alice and Bob are playing a game. Alice starts first. On Alice's turn, she flips a coin. If she gets a heads, she wins. If not,

trapecia [35]

Answer:

The probability that Alice wins the game= $\frac{1}{2}$

Step-by-step explanation:

We are given that Alice and Bob are playing a game .

We have to find the probability that Alice wins the game .

If Alice win when she gets head and lose when she gets tail.Bob wins when she gets tail and she lose when she gets head.

Total results in a coin=Head, tail=2

Number of head in a coin=1

Number of tail in a coin= 1

Probability is defined as the possibility of an event that occurred

$P(E)=\frac{Number\;of\;favourable\;cases}{total\;of\;cases}$

The probability that Alice wins the game= $\frac{Number\;of\;favourable\;cases}{Total\;number\;of\;cases}$

The probability that Alice wins the game= $\frac{number \;of \;heads}{Total\; results}$

The probability that Alice wins the game= $\frac{1}{2}$

8 0

3 years ago