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3 years ago

I need Help Answer quick

Mathematics

1 answer:

Pie3 years ago

5 0

I can’t see the pic clearly

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HELPPP PLEASE!!! IM BEING TIMED!!!

Elena-2011 [213]

Answer:

y=2x+4

Step-by-step explanation:

8=2(6)+b

8=12+b

4=b

5 0

2 years ago

Latoya's annual salary is $26,000. A total of $7352.24 will be deducted for taxes and health insurance. She will receive her pay

Anna71 [15]

Step-by-step explanation:

Lets translate this word problem into math.

"Latoya's annual salary is $26,000" = We start with the number 26,000

"A total of $7352.24 will be deducted for taxes and health insurance" = It's the number we started with "deducted" (minus) 7352.24

"She will receive her paycheck monthly in 12 equal installments" = Our number will be divided by 12

"How much will she get paid with each paycheck?" = "Find answer pls thx"

To put it all together...

$\frac{26,000-7,352.24}{12}$

Now all we have to do is solve!

$\frac{26,000-7,352.24}{12}$

Subtract.

$\frac{18,647.76}{12}$

Divide.

$1,553.98$

Answer:

Latoya will get paid $1,553.98 with each paycheck.

7 0

2 years ago

9. (X + 8)^2 - 5 = 0

d1i1m1o1n [39]

Answer:

x + 59 = 0

X= -59

Step-by-step explanation:

7 0

3 years ago

What is bigger 3.345 or 3.35 or 3.3

Sidana [21]

3.35 is bigger then 3.345

8 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$

c) In this case, t=0.25, so we recalculate the parameter as:

$\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5$

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

$E(x)=\lambda=1.5$

3 0

3 years ago