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3 years ago

15

The astronomical unit (AU) is the mean distance from the sun to the earth.

2 answers:

Mrac [35]3 years ago

7 0

By definition, we have to
1 AU = 1.5 * 10 ^ 8Km
a comet is 2.3 AU from the earth, which means that we must transform this unit to kilometers.
2.3 AU = (2.3) * (1.5 * 10 ^ 8) = 3.45 * 10 ^ 8km
answer
<span> 3.45 × 10,superscript,8,baseline, km
</span>

zvonat [6]3 years ago

3 0

<span>A. 3.45 x 10^8 km Since 1 AU is 1.5x10^8 and the comet is 2.3 AU away from Earth, the answer is a simple matter of multiplication. So: 1.5x10^8 km * 2.3 = 3.45x10^8 km Of the available options, option "A" matches exactly.</span>

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Multiply using a special product formula (6x-8) (6x+8)

ANEK [815]

The correct answer is B.

6x*6x=36x

-8*+8=-64

Thus, our equation is 36x-64

Hope this helps!

4 0

3 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

Please help me with steps

Kitty [74]

Answer:

12 if x_y

Step-by-step explanation:

12= 3x4 (I'm sorry for this, I need points)

8 0

2 years ago

Calculate the volume of each diagrams.

wariber [46]

The volume of the solid objects are 612π in³ and 1566πcm³

<h3>Volume of solid object</h3>

The given objects are composite figures consisting of two shapes.

The volume of the blue figure is expressed as;

Volume = Volume of cylinder + volume of hemisphere

Volume = πr²h + 2/3πr³

Volume = πr²(h + 2/3r)

Volume = π(6)²(13+2/3(6))

Volume = 36π(13 + 4)

Volume = 612π in³

For the other object

Volume = Volume of cylinder + volume of cone

Volume = πr²h + 1/3πr²h

Volume = π(9)²(15) + 1/3π(9)²(13)

Volume= 81π (15+13/3)
Volume= 1566πcm³

Hence the volume of the solid objects are 612π in³ and 1566πcm³

Learn more on volume of composite figures here: brainly.com/question/1205683

#SPJ1

8 0

2 years ago

-6a-7<br><img src="https://tex.z-dn.net/?f=%20-%206a%20-%207%20%5Cleqslant%2017" id="TexFormula1" title=" - 6a - 7 \leqslant 17"

seropon [69]

$-6a-7\leq17\ \ \ \ |+7\\\\-6a\leq24\ \ \ \ |\text{change the signs}\\\\6a\geq-24\ \ \ |:6\\\\a\geq-4$

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3 years ago