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Alekssandra [29.7K]

3 years ago

10

If a right triangle has side lengths of 3 cm and 7 cm, what is the length of the hypotenuse? brainliest will report if answer is

not right

1 answer:

Neko [114]3 years ago

8 0

Answer:

Solution given:

length[a]=3cm

base(b)=7cm

hypotenuse [c]=?

we have

by using Pythagoras law

a²+b²=c²

3²+7²=c²

c=√58=7.61m

<u>the length of the hypotenuse is 7.61</u><u> </u><u>o</u><u>r</u><u> </u><u>7</u><u>.</u><u>6</u><u> </u><u>o</u><u>r</u><u>8</u><u>m.</u>

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2 years ago

I need help completing this problem ASAP

Evgen [1.6K]

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sqrt(45) + sqrt(125)

Rewriting

sqrt(9*5) + sqrt( 25 *5)

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A travelling salesman sells milkshake mixing machines and on average sells 8.9 machines per month. He needs to sell at least 3 m

Goshia [24]

Answer:

0.67% probability he will have to shut down after this month

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

On average sells 8.9 machines per month.

So $\mu = 8.9$

Using the Poisson distribution, what is the probability he will have to shut down after this month

If he sells less than 3 machines.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-8.9}*8.9^{0}}{(0)!} = 0.0001$

$P(X = 1) = \frac{e^{-8.9}*8.9^{1}}{(1)!} = 0.0012$

$P(X = 2) = \frac{e^{-8.9}*8.9^{2}}{(2)!} = 0.0054$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0001 + 0.0012 + 0.0054 = 0.0067$

0.67% probability he will have to shut down after this month

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3 years ago