Ask question

Ask question

All categories

Alekssandra [29.7K]

3 years ago

10

If a right triangle has side lengths of 3 cm and 7 cm, what is the length of the hypotenuse? brainliest will report if answer is

not right

1 answer:

Neko [114]3 years ago

8 0

Answer:

Solution given:

length[a]=3cm

base(b)=7cm

hypotenuse [c]=?

we have

by using Pythagoras law

a²+b²=c²

3²+7²=c²

c=√58=7.61m

<u>the length of the hypotenuse is 7.61</u><u> </u><u>o</u><u>r</u><u> </u><u>7</u><u>.</u><u>6</u><u> </u><u>o</u><u>r</u><u>8</u><u>m.</u>

You might be interested in

What is the approximate area of the circle shown below?

ivolga24 [154]

The answer is 20,106 basically “B”

3 0

3 years ago

Teresa counted the number of tomatoes in 9 baskets at a vegetable stand. The list shows the data. 11, 12, 8, 12, 8, 8, 11, 11, 9

barxatty [35]

Mean is 4
Median is 11

4 0

2 years ago

When twice a certain number is added to 7,the result is less than 17.what is the number.

EleoNora [17]

Answer: 2?

Step-by-step explanation:

7 0

3 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

Ms. Barclay orders birthday cupcakes for the month of June from an online vendor. Each cupcake costs $1.25 and there is a one-ti

artcher [175]

Answer:

Ms. Barclay ordered 9 cupcakes.

Step-by-step explanation:

$1.25x9=11.25

11.25+3.25=$14.50

8 0

3 years ago