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2 years ago

The value of y varies directly with x, and y= -10 when x=40. Identify the value of y when x=-5

Mathematics

1 answer:

scoray [572]2 years ago

8 0

Answer:

y = 1.25

Step-by-step explanation:

Use the direct variation equation y = kx, and solve for k:

y = kx

-10 = k(40)

-0.25 = k

So, the equation is y = -0.25x. Solve for y when x = -5

y = -0.25x

y = -0.25(-5)

y = 1.25

So, y = 1.25 when x = -5

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18.25=4(1.5-3.75x)-.25(4x-5) wat is x?

sdas [7]

The answer is x= - 11/ 16
You can check this by plugging in x for -11/16

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3 years ago

Please answer CORRECTLY for brainliest guarantee. If your answer is not correct or does not have a explanation I will report you

Scorpion4ik [409]

Answer:

c. 45.34ft

Step-by-step explanation:

When leg one of the triangle is 15ft and leg two is 17 ft you would take 17^2 + 15^2 and then you find the square root of that (514) to get the hypotenuse of the triangle. After that you multiply by two to account for the 2/2 sqaure foot per each unit

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3 years ago

What is the written form of the fraction 1/3 ? Patty stirred 1/3 cup of milk into the macaroni and cheese. A. one-third B. one t

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3 years ago

Read 2 more answers

Help!! Which of the following best represents Z1 • Z2 select all that apply

AURORKA [14]

$z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)$

$z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}$

$\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\$

$Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)$

On simplifying, we get

$Z_1* Z_2 =-3\sqrt{2}$

<h2>Therefore, correct option is 1st option.</h2>

3 0

3 years ago

Please help and show all work so I can fully understand it, thanks.

seraphim [82]

Answer:

$\frac{1}{m-4}$

Step-by-step explanation:

$\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}$

Factor the equation:

$\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}$

$\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}$

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

Simplify, take out common terms that are found on both the numerator and denominator

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

$\frac{1}{m-4}$

4 0

3 years ago