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SpyIntel [72]
3 years ago
9

Someone please help me

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0
It’s A
Because the line of the graph is only going on 3, they are all positive 3 and the equation what x = 3.which mean they are all equal.
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Rashid [163]
Slope is 2/-1 or -2. Because you go up twice and then you go left once.
4 0
3 years ago
Read 2 more answers
Please answer this please
cluponka [151]

Step-by-step explanation:

<h3>1. x² + 4 = (x+2)² </h3>

<h3> : x² + 4 = x² + 4 (Yes)</h3>

<h3>2. (2x+6)²= 4(x+3)²</h3>

<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>

<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>

<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>

<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>

<h3> : x²-2x+y² = (a-b)(a+b) </h3>

<h3>Therefore, its not true statement!</h3>
4 0
3 years ago
ILL GIVE BRAINLIEST! FIND THE MEASURE OF B AND SHOW YOUR WORK. If you dont show the equation you used to get your answer then i
lutik1710 [3]

Answer:

23 and 131

Step-by-step explanation:

For the first one. Since a whole entire angle thingie is 360, subtract 243 and 94 from 360. Answer is 23 :)

For the second one. This is a supplementary angle. 180- 49 is 131. Your done!

7 0
3 years ago
What is the common difference in the following arithmetic sequence?7,3,-1,-5
Natasha2012 [34]

Answer:

-4

Step-by-step explanation:

The common difference is found by subtracting the second term from a previous term

So...

3-7 would give the common difference = -4

-1-3 would give the common difference= -4

-5-1 would give the common difference= -4

5 0
3 years ago
Use the definition of a derivative to find f’(x).
tatyana61 [14]

Answer:

f'(x) = -\frac{9}{x^2}

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x)  = $\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $  \hspace{0.2cm}

        = $\lim_{h\to 0} \frac{\frac{9}{x+h}  - \frac{9}{x} }{h}  =  \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} =  \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)}  =  $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$

7 0
3 years ago
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