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Olegator [25]
3 years ago
7

Find the electronic configration for number 1 and 2

Chemistry
2 answers:
Elena-2011 [213]3 years ago
6 0

Answer:

Explanation:

Can you show us the problems

tresset_1 [31]3 years ago
6 0
You didn’t show a picture to solve


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A 55.0g sample of iron (III) filings is reacted with 23.8g of powdered sulfur (S8). How much iron (III) sulfide in moles would b
Margaret [11]

Answer:

0.744 mol

Explanation:

the balanced equation for the reaction is

8Fe + S₈ ---> 8FeS

molar ratio of Fe to S₈ is 8:1

number of moles of Fe - 55.0 g / 56 g/mol = 0.98 mol

number of moles of S - 23.8 g / 256 g/mol = 0.093 mol

if we are to assume that S₈ is the limiting reactant

if 1 mol of S₈ reacts with 8 mol of Fe

then 0.093 mol of S₈ reacts with - 8 x 0.093 mol = 0.744 mol of Fe

however there's 0.98 mol of Fe present but only 0.744 mol of Fe is needed

therefore Fe is in excess and S₈ is the limiting reagent

molar ratio of S₈ to FeS is 1:8

then 0.093 mol of S₈ reacts with - 8 x 0.093 = 0.744 mol of FeS

number of FeS moles produced is 0.744 mol

8 0
3 years ago
Read 2 more answers
70 POINTS AND BRAINLIEST ASAPPPP
Crank

Answer:

is there anyway u could ut it in diffrent words i do not unders stand

Explanation:

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