All categories

3 years ago

1. What type of reaction is this?

Chemistry

2 answers:

NNADVOKAT [17]3 years ago

7 0

Answer:

B if you meant $H_{2}O$ -> $H_{2} +O_{2}$

Explanation:

A. Synthesis: reaction where two or more reactants combine to form one product. A+B->AB

B. Decomposition: reaction where a single compound reacts to form more than one product. AB-> A+B

C. Combustion: any reaction in which a substance reacts with oxygen gas. (needs $O_{2}$ )

D. Single replacement: a type of reaction where one element replaces a similar element within a compound. Reaction is always an element and a compound.

E. Double replacement: a type of reaction where the ions of two compounds exchange places in an aqueous solution to form two new compounds. AB+CD->AD+CD

AnnZ [28]3 years ago

5 0

It is a decomposition reaction I think

You might be interested in

What is Type of compound of ICI

valentina_108 [34]

Answer:

ICI 204448 hydrochloride | C23H27Cl3N2O4 | CID 129407 - structure, chemical names, physical and chemical properties, classification, patents, literature, etc...

hope this helps!! have an amazing day <3

8 0

3 years ago

Read 2 more answers

Need help !!!!! ASAP

Korolek [52]

<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

$V_{2}=2.84L$

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.

The law is defined by the following equation:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}$

Where,

$P_{1}$ is the first pressure.

$V_{1}$ is the first volume.

$T_{1}$ is the first temperature.

$P_{2}$ is the second pressure.

$V_{2}$ is the second volume.

$T_{2}$ is the second temperature.

So, we are given the following information:

$V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K$

Then, isolating the new volume, and substituting, we have:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L$