1. What type of reaction is this?
2 answers:
Answer:
B if you meant ->
Explanation:
A. Synthesis: reaction where two or more reactants combine to form one product. A+B->AB
B. Decomposition: reaction where a single compound reacts to form more than one product. AB-> A+B
C. Combustion: any reaction in which a substance reacts with oxygen gas. (needs )
D. Single replacement: a type of reaction where one element replaces a similar element within a compound. Reaction is always an element and a compound.
E. Double replacement: a type of reaction where the ions of two compounds exchange places in an aqueous solution to form two new compounds. AB+CD->AD+CD
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1.302 moles of carbon dioxide would have to be added
<h3>Further explanation</h3>The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient
The equilibrium constant is based on the concentration (Kc) in a reaction
pA + qB -----> mC + nD
While the equilibrium constant is based on partial pressure
The value of Kp and Kc can be linked to the formula '
R = gas constant = 0.0821 L.atm / mol.K
=n = number of product coefficients-number of reactant coefficients
An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O
- We determine Kc (constant concentration)
- the amount of carbon monoxide to 0.300 mol
Reaction :
CO +H₂O ⇔ CO₂ + H₂
initially 0.2 0.2 0.75+x 0.75
reaction 0.1 0.1 0.1 0.1
product 0.3 0.3 0.65+x 0.65
an equilibrium constant brainly.com/question/9173805
Calculate the value of the equilibrium constant, Kc
Concentration of hi at equilibrium
Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient
Explanation:
to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.
molar mass of sucrose is 342.3 g/mol.
now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose
735g/(342.3g/mol)=2.147mol
theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...
2.147mole yield 2.147*4mol=8.588mol
now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...
so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g
but we only obtained 310.5g...so percentage we have is
78.47%
if there is trouble with molar mases I used....use what you calculated...
If my explanation is good enough...please mark it as brainliest.thanks