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Montano1993 [528]
4 years ago
15

What is the difference between a amalgam and alloy.

Chemistry
1 answer:
Gennadij [26K]4 years ago
8 0
Combinations of different metals form alloys. An alloy composed by mercury and other metal (or metals) forms amalgam. When a true alloy is formed, the component metals are mixed together at a temperature which is greater than the melting point of all of them.Apr 7, 2017
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Draw the structures of organic compounds a and b omit all by products thf
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The reaction is shown below,

Step 1: Hydration of Alkene:
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Step 2: Oxidation of Primary Alcohol:
                                                          In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (PCC) and Acetaldehyde is produced.

Step 3: Reduction of Acetaldehyde followed by Oxidation:
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6 0
3 years ago
Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?
kakasveta [241]
The Bohr Model, which was proposed by Niels Bohr in 1913
6 0
3 years ago
oxidul de cupru este folosit la colorarea sticlei si a emailurilor carora le imprima o culoare verde-albastruie.Calculeaza masa
Pani-rosa [81]

Answer:

english

Explanation:

5 0
3 years ago
1. Convert 67500 mg to the unit hg
Mice21 [21]

Answer:

0.675

Explanation:

4 0
4 years ago
17. The correct arrangement of the following elements in order of
tatuchka [14]

Answer:

Got your back

Explanation:

If the ions derived from different atoms are isoelectronic species, then they all have same number of electrons in their electronic shells and will have got same electronic configuration but their nuclear charge will differ because of their difference in number of protons in the nucleus. With increase in number of protons in the nucleus the electrons are more attracted towards nucleus thereby causing the decrease in ionic radius. On this principle our problem will be solved

The given ions are

7N-3

→no. of proton

=7

and

no of electron

=10

8O-2

→

no. of proton

=8

and

no of electron

=10

9F-→

no. of proton=9

and no of electron=10

11Na→

no. of proton=11

and no of electron=10

12 Mg-3→

no. of proton=12 and

no of electron=10

Hence the increasing order of ionic radius is

12Mg-3<11Na+<9F-<8O-2<7N-3

To rmember ->For isoelectronic species lower the nuclear charge higher the radius

8 0
3 years ago
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