<span> The lower and upper bounds of the confidence intervals must be equally distanced from the mean
so it will be
</span><span>70.9 - 73.1
</span>hope it helps
The question seems incomplete ; as the total number of tickets to be sold isn't given.
Answer:
61 / X
Step-by-step explanation:
Let's take the total Number of tickets to be sold as : X
Number of tickets sold on Thursday = 47
Number sold on Friday = 14
Fraction of tickets available for sale on Saturday :
(Total number of tickets already sold) / Total number of tickets to be sold
(Thursday + Friday sales) / total number of tickets to be sold
Fraction available for sale on Saturday = (47+14) / X
Fraction available for sale on Saturday = 61 / X
Kindly put value of x = total number of tickets available for sale to get the exact fraction.
In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
Answer:
A,B,C,D
Step-by-step explanation:
I say all of them because all of them are spelled correctly but if it incorrect i'm very sorry
Answer:
can you please give more info
Step-by-step explanation: