Answer:
![\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B62%2B63%2B68%2B72%2B79%2B80%2B83%2B93%2B94%2B95%7D%7B10%7D%3D%2078.9)
![|62-78.9| = 16.9](https://tex.z-dn.net/?f=%20%7C62-78.9%7C%20%3D%2016.9)
![|63-78.9| = 15.9](https://tex.z-dn.net/?f=%20%7C63-78.9%7C%20%3D%2015.9)
![|68-78.9| = 10.9](https://tex.z-dn.net/?f=%20%7C68-78.9%7C%20%3D%2010.9)
![|72-78.9| = 6.9](https://tex.z-dn.net/?f=%20%7C72-78.9%7C%20%3D%206.9)
![|79-78.9| = 0.1](https://tex.z-dn.net/?f=%20%7C79-78.9%7C%20%3D%200.1)
![|80-78.9| = 1.1](https://tex.z-dn.net/?f=%20%7C80-78.9%7C%20%3D%201.1)
![|83-78.9| = 4.1](https://tex.z-dn.net/?f=%20%7C83-78.9%7C%20%3D%204.1)
![|93-78.9| = 14.1](https://tex.z-dn.net/?f=%20%7C93-78.9%7C%20%3D%2014.1)
![|94-78.9| = 15.1](https://tex.z-dn.net/?f=%20%7C94-78.9%7C%20%3D%2015.1)
![|95-78.9| = 16.1](https://tex.z-dn.net/?f=%20%7C95-78.9%7C%20%3D%2016.1)
![MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}](https://tex.z-dn.net/?f=%20MAD%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%7CX_i%20-%5Cbar%20X%7C%7D%7Bn%7D)
And replacing we got:
![MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12](https://tex.z-dn.net/?f=%20MAD%20%3D%5Cfrac%7B16.9%2B15.9%2B10.9%2B6.9%2B0.1%2B1.1%2B4.1%2B14.1%2B15.1%2B16.1%7D%7B10%7D%3D%2010.12)
And the best anwer is
10.12
Step-by-step explanation:
We have the following data given:
62 63 68 72 79 80 83 93 94 95
And we need to begin finding the mean with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B62%2B63%2B68%2B72%2B79%2B80%2B83%2B93%2B94%2B95%7D%7B10%7D%3D%2078.9)
Now we can find the mean absolute deviation like this:
![|62-78.9| = 16.9](https://tex.z-dn.net/?f=%20%7C62-78.9%7C%20%3D%2016.9)
![|63-78.9| = 15.9](https://tex.z-dn.net/?f=%20%7C63-78.9%7C%20%3D%2015.9)
![|68-78.9| = 10.9](https://tex.z-dn.net/?f=%20%7C68-78.9%7C%20%3D%2010.9)
![|72-78.9| = 6.9](https://tex.z-dn.net/?f=%20%7C72-78.9%7C%20%3D%206.9)
![|79-78.9| = 0.1](https://tex.z-dn.net/?f=%20%7C79-78.9%7C%20%3D%200.1)
![|80-78.9| = 1.1](https://tex.z-dn.net/?f=%20%7C80-78.9%7C%20%3D%201.1)
![|83-78.9| = 4.1](https://tex.z-dn.net/?f=%20%7C83-78.9%7C%20%3D%204.1)
![|93-78.9| = 14.1](https://tex.z-dn.net/?f=%20%7C93-78.9%7C%20%3D%2014.1)
![|94-78.9| = 15.1](https://tex.z-dn.net/?f=%20%7C94-78.9%7C%20%3D%2015.1)
![|95-78.9| = 16.1](https://tex.z-dn.net/?f=%20%7C95-78.9%7C%20%3D%2016.1)
And finally we can find the mean abslute deviation with the following formula:
![MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}](https://tex.z-dn.net/?f=%20MAD%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%7CX_i%20-%5Cbar%20X%7C%7D%7Bn%7D)
And replacing we got:
![MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12](https://tex.z-dn.net/?f=%20MAD%20%3D%5Cfrac%7B16.9%2B15.9%2B10.9%2B6.9%2B0.1%2B1.1%2B4.1%2B14.1%2B15.1%2B16.1%7D%7B10%7D%3D%2010.12)
And the best anwer is
10.12
Answer:
27/462
OR
.058
Step-by-step explanation:
the probability that the first student, selected at random, is a nursing student is 3/22.
the probability that the second student, selected at random from the remaining students, is an accounting major is 9/21.
the probability the first student chosen is a nursing student and the second student chosen is an accounting major is therefore 3/22 * 9/21 = 27/462.
To answer problems like this you have to use binomial:
P (x > 1) = 1 – p (0
< x < 1) > .7
So:
1 – p (0) – p (1) >
.7
1 – (3/ 4) ^n – (3/ 4)
^n (n – 1 ) (1/ 4) > .7
Therefore n > 5.185,
and the smallest value of n so that we can satisfy the given condition is 6
(rounded up)
<span> </span>
Answer:
yes your absolutely right
Step-by-step explanation:
you just are