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3 years ago

What is the area of the trapezoid?

Mathematics

1 answer:

Aloiza [94]3 years ago

6 0

Answer:

Step-by-step explanation:

A = $\frac{a+b}{2\\}$ h

= $\frac{3+5}{2}$ · 3

= 12 ft

I hope this help

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I go bowling every week and keep track of how many strikes i get: 2,0,4,7,7,0,1,0 Find the mode median and mean of this set of d

natima [27]

Answer:

Mode is 0
Median is 1
Mean is 2.625

Step-by-step explanation:

To find the mode, or modal value, it is best to put the numbers in order. A number that appears most often is the mode.
0, 0, 0, 1, 2, 4, 7, 7 = mode is 0

To find the Median, place the numbers in value order and find the middle number.
0 , 0 , 0 , 1 , 2 , 4 , 7 , 7 = median is 1

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are.
0 + 0 + 0 + 1 + 2 + 4 + 7 + 7 / 8 = mean is 2.625

5 0

3 years ago

Percents-Starting with A, what is the order of letters for the scavenger hunt. Remember, you should be using all letters and whe

ad-work [718]

Answer:

yes

Step-by-step explanation:

yes

4 0

3 years ago

Use the following function rule to find f(0). f(x)= -9 (3)^x f (0 ) =

AlladinOne [14]

Step-by-step explanation:

Substitute f(0) into the function:

$f(0) = - 9(3)^{0}$

Include exponent:

$f(0) = - 9(1)$

Multiply:

$f(0) = - 9$

7 0

2 years ago

Mr.anson has $38 in his wallet what is the least number of bills he can have

Alexandra [31]

Answer:

I am guessing , atleast 8

Step-by-step explanation:

5 0

3 years ago

[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =

kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = $1-\frac{_{n}^{12}\textrm{P}}{12^2}$

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= $\frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})$

= $0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1$

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0

3 years ago