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castortr0y [4]
3 years ago
10

PLEASE HELP AGAIN IT IS THE MATH AND PLEASE GIVE ME REAL ANSWERS!

Physics
2 answers:
denis23 [38]3 years ago
5 0

Answer:

Everyone would get 2 1/4 cupcakes because if you split up each cupcake by 4, (In four different pieces) everyone would get 9/4 slices. Change to a mixed number to get 2 1/4

Explanation:

podryga [215]3 years ago
5 0

Answer:

the answer is 2 1/4 is shared

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Ted Williams hits a baseball with an initial velocity of 120 miles per hour (176 ft/s) at an angle of θ = 35 degrees to the hori
lys-0071 [83]

Answer: the maximum heigth of the stadium at ist back wall is 151.32 ft

Explanation:

1. use the position (x) equation in parobolic movement to find the time (t)

565 ft = [frac{176 ft}{1 s\\}[/tex] * cos (35°)  * t

t= 3.92 s

2. use the position (y) equation in parabolic movement to find de maximun heigth  the ball reaches at 565 ft from the home plate.

y= [[frac{176 ft}{1 s\\}[/tex] * sen (35°) * 3.92 s] - \frac{32.2 ft/s^{2} *3.92 s^{2}  }{2}

y= 148.32 ft

3. finally add the 3 ft that exist between the home plate and the ball

148.32 ft + 3 ft = 151.32

6 0
3 years ago
how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch
Anika [276]

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

\rho = \frac{PM}{RT}

\frac{dP}{dz} = -\rho g\\\\

where;

  • <em>ρ is density</em>
  • <em>T is temperature</em>
  • <em>dP is rate of change of vertical  pressure</em>

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Learn  more here:brainly.com/question/25395377

5 0
3 years ago
What factors determine the amount of air resistance an object experiences?
geniusboy [140]
The pressure of the air at the way its blowing

3 0
3 years ago
A 65.8-kg person throws a 0.0413 kg snowball forward with a ground speed of 32.5 m/s. A second person, with a mass of 58.7 kg, c
guapka [62]

Answer:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

Explanation:

The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:

First Person

(65.8\,kg)\cdot (2.51\,\frac{m}{s}) = (65.8\,kg)\cdot v_{1} + (0.0413\,kg)\cdot (32.5\,\frac{m}{s} )

Second Person

(0.0413\,kg)\cdot (32.5\,\frac{m}{s})+(58.7\,kg)\cdot (0\,\frac{m}{s})=(0.0413\,kg+58.7\,kg)\cdot v_{2}

The final velocities of the two people after the snowball is exchanged is:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

6 0
3 years ago
Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the
Assoli18 [71]

Answer:

Part a)

\rho = 3\epsilon_0 k r^2

Part b)

Q = 4\pi \epsilon_0kR^5

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

E = kr^3 \hat r

now electric flux through a spherical surface of radius r is given as

\phi = E. A

\phi = kr^3(4\pi r^2)

now by Guass law we know that

E.A = \frac{q}{\epsilon_0}

q = 4\pi \epsilon_0kr^5

now volume charge density is given as

\rho = \frac{q}{\frac{4}{3}\pi r^3}

\rho = 3\epsilon_0 k r^2

Part b)

Total charge inside the radius R is given as

Q = 4\pi \epsilon_0kR^5

7 0
3 years ago
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