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Trava [24]
2 years ago
15

Help please I’ll mark as brainliest

Physics
1 answer:
kirza4 [7]2 years ago
6 0

Answer:

yes

Explanation:

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The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp
IRISSAK [1]

Answer:

a

   k    =  11600000 N/m

b

   \Delta  L  =  3.2323 *10^{-5} \ m

c

  F =  3750.28 \  N  

Explanation:

From the question we are told that

    The Young modulus is  E =  1.4 *10^{10} \  N/m^2

     The length is  L  =  0.35 \ m

      The  area is  2.9 \ cm^2  =  2.9 *10^{-4} \ m ^2

   

Generally the force acting on the tibia is mathematically represented as

       F =  \frac{E *  A  *  \Delta  L }{L}    derived from young modulus equation

Now this force can also be mathematically represented as

      F =  k *  \Delta  L    

So

     k    =  \frac{E *  A  }{L}

substituting values

     k    =  \frac{1.4 *10^{10} *  2.9 *10^{-4}  }{ 0.35}

     k    =  11600000 N/m

    Since the tibia support half the weight then the force experienced by the tibia is  

        F_k  =  \frac{750 }{2}  =  375 \  N

 From the above equation the extension (compression) is mathematically represented as

          \Delta  L  =  \frac{ F_k  *  L  }{ A *  E }        

substituting values

           \Delta  L  =  \frac{  375   *  0.35  }{ (2.9 *10^{-4}) *   1.4*10^{10} }

           \Delta  L  =  3.2323 *10^{-5} \ m

From the above equation the maximum force is  

        F =  \frac{1.4*10^{10} *  (2.9*10^{-4})  *  3.233*10^{-5} }{ 0.35}  

         F =  3750.28 \  N  

4 0
3 years ago
Pls help i dont know this
tatuchka [14]

Answer:

can you make it bigger

Explanation:

i can't see it

5 0
3 years ago
Plz help help
Nezavi [6.7K]

Answer:

4

Explanation:

8 0
2 years ago
A bus starts from village A at 7:00 am and reaches village B at 8:30 am. If the distance between the villages A and B is 60 km.
SVEN [57.7K]

1.1111111111

Explanation:

v=s/t

t=8:30-7:00=1:30

convert to second=5400second

s=60km covert to meter=6000

6000/5400=1.11111111

5 0
2 years ago
Read 2 more answers
State advantages of ultrasonic sound in determining the depth of the ocean ​
agasfer [191]

Answer:

It has <u>greater accuracy than other nondestructive methods in determining the depth of internal flaws and the thickness of parts with parallel surfaces.</u>

Explanation:

Hope this helps you!

5 0
2 years ago
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