Question

A ball is thrown with an initial speed of 10. Meters per second. At what angle above the horizontal should the ball be thrown to reach the greatest height?

Answer 1

The initial speed doesn’t matter.  To reach the maximum height, you need to launch straight up ... 90 degrees above horizontal.

Answer 2

Answer:

90 degree

Explanation:

The height for the projectile motion is given by

H = u^2 Sin^2 theta/ 2g

Height is maximum when sin theta is maximum.

Sin theta is maximum when it's value is 1.

So the value of theta is 90 degree.