you have to substitiute volume of the ballon
Answer:
2. 200N
3.50kg
4.700N
Explanation:
Weight is another word for the force of gravity
Weight is a force that acts at all times on all objects near Earth.
F=m*g
where g=acceleration due to gravity
2. due to the gravitational fields of the earth , assume gravitational acceleration=10m/s2
F=20*10= 200N
3.same as above
mass=Force/gravitational acceleration
mass=500/10 = 50kg
4.force=mass*gravitational acceleration
force=70*10=700N
80 km per hour i believe. i’ll admit i’m american so we don’t use km lol, but the math should be the same. total distance = 120km, and total time = 1.5 hours. 120/1.5 = 80.
When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth, the type of force they are experiencing is <span>A. tension. Tension is the opposite of compression which is pulling of the astronaut from the ground or Earth</span>
Answer:

Explanation:
Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:
(1)
Where:






In this case:

Because the dog jumps horizontally
Let's asume the gravity constant as:


Because when the dog reach the base the height is 0


Now let's replace the data in (1)

Isolating t:

Finally let's find the horizontal displacement using this equation:

Replacing the data:
