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aniked [119]
3 years ago
11

Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters

along the incline, how much work will he do on the box?
Physics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

(60 newtons) x (10 meters)  =  600 joules.

Explanation:

melomori [17]3 years ago
4 0

Pretty sneaky, I must say !  

                   Work = (force) x (distance)

That formula says nothing about the directions of the force OR
the distance.  As long as they're both in the same direction, they
can both be horizontal (sliding a crate on the floor), vertical (lifting
something), or on any slant in between.

Roger's force and distance are both in the same direction ... the
direction of the incline ... so

                   Work = (60 newtons) x (10 meters)  =  600 joules.

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The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

KE = 0.5 * mv^2 =0.5 * 15.0-kg * (1.10 m/s)^2 = 9.1 J

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Learn more about thermal energy due to friction:brainly.com/question/7207509

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A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

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And the longitudinal stress would be

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\sigma_l = \frac{75\times 8}{4\times 0.25}

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The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

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