Um I believe that it goes on top of the hoof
The velocity of the rock after 2s is 12.56 m/s.
The velocity of the rock at 25 m upwards is 14.68 m/s.
The velocity of the rock at 25 m downwards is -15.97 m/s.
The given parameters;
- <em>velocity of the rock, u = 20 m/s</em>
- <em>height of the rock, h = 20t - 1.8t²</em>
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The velocity of the rock after 2s is calculated as follows;

The velocity of the rock when the height is 25 m:
h = 20t - 1.8t²
25 = 20t - 1.8t²
1.8t² - 20t + 25 = 0
solve for the time of motion "t" using quadratic formula
a = 1.8, b = -20, c = 25

The value of t that will give 25 m upwards using the motion model is 1.43 s;
h = 20(1.43) - 1.86(1.43)² = 25 m
The velocity of the rock at 25 m upwards (t = 1.43 s) is calculated as follows;

The velocity of the rock at 25 m downwards (t = 9.67 s) is calculated as;

Learn more here:brainly.com/question/25233377
Draw a free body diagram to help you visualize. draw the object and use arrows to label and determine where all the forces acting upon it will be. then u add up the sum of all forces. if two forces of equal magnitude and opposite directions will cancel each other out.
Let's call the first number n, and the second number m.
n = 2m + 9 (9 more than twice the second number)
If the sum is 129, that means n + m = 129.
Now we can substitute the first expression (n = 2m + 9) into the second expression (n + m = 129), replacing the n.
(2m + 9) + m = 129
3m + 9 = 129
3m = 129 - 9
3m = 120
m = 120/3
m = 40
Now that we know m, we can find out n by replacing the m with 40 in the first expression (n = 2m + 9):
n = 2(40) + 9
n = 80 + 9
n = 89.
Therefore, n = 89, and m = 40.