How much weight can be placed on the spring so that the end of the spring is 2m above the ground?

Physics

1 answer:

Ronch [10]2 years ago

8 0

The weight must be 288N placed on the end of the spring when it is 2m from the ground.

<h3>What is gravitational potential energy?</h3>

If an object is lifted, work is done against gravitational force. The object gains energy.

Given is a spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground. The final height of weight above the ground, h =2m

Using Hooke's law, expressed as

Force, F = k (x₂-x₁).

Put the values, we get

F = 48 (8-2)

F = 288 N

This force applied on the spring is equal to the weight placed on the spring.

Weight W= 288N.

Thus, the weight must be 288N.

Learn more about gravitational potential energy.

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In this system the energy is conserved

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