What are the applications of pascal's principle
1 answer:
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Answer:
Capacitance of the second capacitor = 2C
Explanation:
Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.
Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.
We have
Similarly for capacitor 2
Capacitance of the second capacitor = 2C
Total resistance=R1+ R2= 6Ω
Voltage=12v
Current =
Current= 2A
In a series circuit, equal current passes through every resistance.
Answer is option A
Voltage=12v
Current =
Current= 2A
In a series circuit, equal current passes through every resistance.
Answer is option A